Understanding Dirac Delta Squares: Clarifying Doubts

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SUMMARY

The discussion clarifies the mathematical interpretation of the product of Dirac delta functions, specifically the expression \(\delta(x-x_1)\delta(x-x_2)\). It establishes that the integral \(\int dx \;\delta(x-x_1)\delta(x-x_2) = \delta(x_1-x_2)\) is valid, emphasizing that the Dirac delta function only holds meaning within an integral context. The conversation highlights that the value of this expression is not zero or infinity but rather depends on the relationship between \(x_1\) and \(x_2\) when integrated.

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hermitian
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hi,

may someone help me to clarify my doubts...

in my work, i encounter diracdelta square [tex]\delta(x-x_1)\delta(x-x_2)[/tex] i am not sure what it means... it seems if i integrate it

[tex]\int dx \;\delta(x-x_1)\delta(x-x_2) = \delta(x_1-x_2)[/tex] is either zero of infinity.

is this correct?

thanks
 
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Technically, saying that it has "value zero or infinity" doesn't make sense. Any Dirac delta only makes sense under an integral sign (although in physics, we tend to think of it as being an "infinite spike with a finite area").

It is correct that
[tex] \int dx \;\delta(x-x_1)\delta(x-x_2) = \delta(x_1-x_2)[/tex]

So, again, this expression again only makes sense inside an integral, like
[tex]\int dx_1 \int dx \; \delta(x - x_1) \delta(x - x_2) = \int dx_1 \; \delta(x_1 - x_2)[/tex]
which is one or zero (depending on whether or not x2 lies in the integration interval of the x1 integral).
 

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