Understanding E Multiplication: Solving Odd Equations with Exponents

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Homework Help Overview

The discussion revolves around the manipulation of exponential expressions involving the base \( e \) and the application of exponent rules. Participants are examining the validity of certain algebraic transformations and their implications in the context of equations involving exponents.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to verify the correctness of their algebraic manipulations involving \( e^{2t} \) and \( 2e^{2t} \). Questions arise regarding the transition from \( 3e^{2t} \) to \( e^{4t} \) and the handling of coefficients in the expressions.

Discussion Status

There is an ongoing exploration of the algebraic properties of exponential functions, with some participants providing insights into the rules governing exponentiation. Multiple interpretations of the expressions are being discussed, and there is a recognition of the need for clarification on certain steps in the calculations.

Contextual Notes

Some participants express confusion due to the late hour, which may affect their ability to process the mathematical concepts being discussed. There are mentions of missing factors and potential errors in the initial expressions that are under scrutiny.

Pengwuino
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[tex] \frac{{{\rm e}^{{\rm 2t}} }}{{\sqrt {e^{4t} + t} }}*2e^{2t} = \frac{{{\rm 2e}^{{\rm 4t}} }}{{\sqrt {e^{4t} + t} }}[/tex]
Is that true? What am i not realizing here...
 
Last edited:
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Pengwuino said:
[tex] \frac{{{\rm e}^{{\rm 2t}} }}{{\sqrt {e^{4t} + t} }}*2e^{2t} = \frac{{{\rm e}^{{\rm 4t}} }}{{\sqrt {e^{4t} + t} }}[/tex]
Is that true? What am i not realizing here...

you left out the factor of 2 in the numerator
 
oops yah i did... ill fix that

but is that true? I can't seem to grasp it... and its midnight so i don't think i will be able to easily realize what's going on

I was thinking that it should just be 3e^2t... and I don't understand how it just got turned into e^4t
 
Pengwuino said:
oops yah i did... ill fix that
but is that true? I can't seem to grasp it... and its midnight so i don't think i will be able to easily realize what's going on
I was thinking that it should just be 3e^2t... and I don't understand how it just got turned into e^4t
No, [tex]e^{2t} + 2 e^{2t}[/tex] would be equal to [tex]3 e^{2t}[/tex].
[tex]e^{2t} * 2 e^{2t} = 2 (e^{2t})^2 = 2 e^{4t}[/tex]

Or for an even more straight forward example,
x + 2x = 3x
x * 2x = 2x^2
 
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youre lucky though, since the [tex]e^x[/tex] function was proven to be exponential, thus it follows the rules of exponents, just like anything else. the rest is just algebra.
[tex]2^2 * 2^2=4 * 4=16=2^4[/tex]
or more generally
[tex]x^a * x^b=x^{ab}[/tex] for all bases that correspond to exponential functions. since the "e" function is exponential, you can use these laws.
have fun
 
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there is a square missing:
[tex]e^{2t} * 2 e^{2t} = 2 (e^{2t})^{2t} = 2 e^{4t^2}[/tex]
 
gerben said:
there is a square missing:
[tex]e^{2t} * 2 e^{2t} = 2 (e^{2t})^{2t} = 2 e^{4t^2}[/tex]

[tex]e^{2t}* e^{2t}=e^{2t+2t}[/tex], not [tex](e^{2t})^{2t}[/tex]
 
Pengwuino said:
oops yah i did... ill fix that

but is that true? I can't seem to grasp it... and its midnight so i don't think i will be able to easily realize what's going on

I was thinking that it should just be 3e^2t... and I don't understand how it just got turned into e^4t

lol i thought that's what the problem was, where did the 2 go? :-p
 

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