Integrating Equations with Exponents: A Challenge

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
Shambles
Messages
14
Reaction score
0

Homework Statement


nzey38.jpg



Homework Equations





The Attempt at a Solution


Homework Statement





Homework Equations


u = 1+tant
du = sec^2(t) dt
dt = du / sec^2(t)

The Attempt at a Solution



It seems like I should be using substitution in the equation, however the exponent is messing things up for me. I recall from derivatives how they interact with the chain rule, but am not sure how this would work backwards in integration. Something like,

I(u^3)(sec^2(t)) = (u^4/4)((sec^2(t)) (tan(t))

Except I haven't gotten rid of the t variable and now have t and u. Any points are welcome.
 
Physics news on Phys.org
Why don't you just substitute u for (1 + tan t) and du for sec^2(t) dt (and take care of the limits of integration, of course)?
 
Ah I see how when I change the limits of integration it removes the nasty sec^2(t) so all I'm left with is the integral of u^3 with u going from 1 to 2. Thanks.