Understanding Even Functions and the Role of Exponential Functions

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Am I correct in thinking exp(−x^2 ) is an even function?

Thanks
 
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micromass said:
Yes! Do you see why?

I think it's because if the x was replaced by (-x) you would have

exp(−(-x)^2 ) = exp(-x^2) which is the same as the original function

It's the same either with a +x or -x making it an even function.
 
ZedCar said:
I think it's because if the x was replaced by (-x) you would have

exp(−(-x)^2 ) = exp(-x^2) which is the same as the original function

It's the same either with a +x or -x making it an even function.

Indeed! :smile: