ZedCar
- 353
- 1
Am I correct in thinking exp(−x^2 ) is an even function?
Thanks
Thanks
The discussion revolves around the characterization of the function exp(−x²) and its classification as an even function within the context of mathematical functions and properties.
There is a general agreement among participants regarding the classification of the function as even, with multiple confirmations of the reasoning provided. However, the discussion remains open to further exploration of the concept.
No specific constraints or missing information have been noted in the discussion.
micromass said:Yes! Do you see why?
ZedCar said:I think it's because if the x was replaced by (-x) you would have
exp(−(-x)^2 ) = exp(-x^2) which is the same as the original function
It's the same either with a +x or -x making it an even function.