Understanding Final Value Theorem in Laplace Transform: Tips & Examples

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The discussion revolves around the Final Value Theorem in the context of Laplace Transforms, particularly its application when complex conjugate poles are present on the imaginary axis. It highlights a contradiction where the theorem is used to find DC gain despite the theorem stating that the output should be undefined in such cases. Participants express confusion over the lack of multiplication by "s" in the process and question the validity of the theorem's application. The mention of a unit step input suggests that "s" can be canceled, but the core issue regarding the definition of the output remains unresolved. The conversation emphasizes the complexities involved in applying the Final Value Theorem correctly in systems with sinusoidal outputs.
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http://fourier.eng.hmc.edu/e102/lectures/Laplace_Transform/node17.html

On that page about final value theorem, it says that;

If there are pairs of complex conjugate poles on the imaginary axis, will contain sinusoidal components and is not defined.

However at the bottom of the page, in order to find the DC gain, it uses Final value theorem.

Ok, well, let's assume somehow he put "0" where he saw "s". How about multiplication with "s" for final value theorem on s domain ?
He didn't even multiplied the H(s) with "s" ?

Confused.
 
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zoom1 said:
http://fourier.eng.hmc.edu/e102/lectures/Laplace_Transform/node17.html

On that page about final value theorem, it says that;



However at the bottom of the page, in order to find the DC gain, it uses Final value theorem.

Ok, well, let's assume somehow he put "0" where he saw "s". How about multiplication with "s" for final value theorem on s domain ?
He didn't even multiplied the H(s) with "s" ?

Confused.

Seems like I missed the unit step input, so "s" will be canceled by "1/s". However still the first question holds. System has complex conjugates lying on the left side of the s plane. Which makes the output sinusoidal. So, x(infinite) shouldn't be defined.
 
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