Understanding Force Problems: Comparing Forces on Driver and Passenger

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SUMMARY

This discussion focuses on the analysis of forces acting on a driver and a passenger during a car collision and the dynamics of an elevator's motion. In the first scenario, a car traveling at 50 km/h collides with a truck, resulting in the driver, restrained by a seatbelt, experiencing a force calculated using F=ma, while the unrestrained passenger collides with the dashboard, leading to different force impacts. The second scenario involves calculating the minimum stopping time for an elevator moving upward at 5.2 m/s, requiring an understanding of normal force and acceleration. The discussion emphasizes the application of Newton's laws and the importance of unit conversion to SI.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with basic physics concepts such as force, mass, and acceleration
  • Ability to convert units to SI (e.g., km/h to m/s)
  • Knowledge of kinematic equations, specifically v² = u² + 2aS
NEXT STEPS
  • Learn how to apply Newton's second law (F=ma) in collision scenarios
  • Study the concept of normal force in accelerating frames of reference
  • Explore kinematic equations for motion analysis in vertical and horizontal contexts
  • Investigate the effects of friction on force calculations in multi-body systems
USEFUL FOR

Physics students, automotive safety engineers, and anyone interested in understanding the dynamics of collisions and motion in vehicles and elevators.

jcumby
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1.) A car moving at 50 km/h collides with a truck, and the front of the car is crushed 1.1 m as it comes to a complete stop. The driver is wearing a steabelt, but the pasenger is not. The passenger, obeying Newton's first law, keeps moving and slams into the dashboard after the car has stopped. If the dashboard compresses 5.0 cm on impact, find and compare the forces exerted on the driver by the seabelt and on the passenger by the dashboard. Assume the two have the same 65 kg mass.

I'm really confused about this one...thus far I have the intertia for both the driver and the passenger at 3250 N (65 kg * 50 km/h), but I'm not even sure if I've done that right.

2.)An elevator moves upward at 5.2 m/s. What is the minimum stopping time it can have if the passengers are to remain on the floor?

I know I need to figure out the normal force on a passenger on the verge of not remaining on the floor, and I know that normal force has to be some combination of mass and acceleration (9.8 + 5.2?), but other than that I'm stuck.

3.) Blocks of 1.0, 2.0, and 3.0 kg are lined up on a table (without friction). A 12 N force is applied to the 1.0 kg block. What force does the 2.0 kg block exert on the 3.0 kg block?

This must have something to do with inertia...but I'm not sure how to begin
 
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jcumby said:
1.) A car moving at 50 km/h collides with a truck, and the front of the car is crushed 1.1 m as it comes to a complete stop. The driver is wearing a steabelt, but the pasenger is not. The passenger, obeying Newton's first law, keeps moving and slams into the dashboard after the car has stopped. If the dashboard compresses 5.0 cm on impact, find and compare the forces exerted on the driver by the seabelt and on the passenger by the dashboard. Assume the two have the same 65 kg mass.

I'm really confused about this one...thus far I have the intertia for both the driver and the passenger at 3250 N (65 kg * 50 km/h), but I'm not even sure if I've done that right.
Convert units to SI and use equation v2=u2+2aS, after you find acceleration (deceleration in this case) for car (ie. also acceleration for driver, as driver moves with car body), and for the passenger, sub acceleration for driver and passenger into F=ma.

2.)An elevator moves upward at 5.2 m/s. What is the minimum stopping time it can have if the passengers are to remain on the floor?

I know I need to figure out the normal force on a passenger on the verge of not remaining on the floor, and I know that normal force has to be some combination of mass and acceleration (9.8 + 5.2?), but other than that I'm stuck.
[/quote]
Use equation a=(v-u)/t -- You know that a=9.8ms-2, v=0 u= -5.2ms-1, considering that down is positive.

3.) Blocks of 1.0, 2.0, and 3.0 kg are lined up on a table (without friction). A 12 N force is applied to the 1.0 kg block. What force does the 2.0 kg block exert on the 3.0 kg block?

This must have something to do with inertia...but I'm not sure how to begin
With no friction? Sounds like a dodgy question, anyone else agree?

Anyway, I'd start by finding out force due to gravity for each mass.

Hope this helps
 

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