Understanding H=L^2 in Quantum Mathematics

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Discussion Overview

The discussion revolves around the mathematical concept of the Hilbert space denoted as H=L^2, specifically in the context of quantum mathematics. Participants explore the definitions and implications of L^2 spaces, including L^2(R^n) and L^2([0,1]), focusing on the nature of square-integrable functions.

Discussion Character

  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant introduces H as L^2(R^n) and seeks clarification on the meaning of L-squared in this context.
  • Another participant explains that L^2 refers to the space of square-integrable functions, providing a link for further reference.
  • A later reply expresses understanding and appreciation for the clarification provided.
  • One participant questions whether L^2(R^n) refers to functions whose square integral converges over the entire real line or just over a sub-interval.
  • Another participant confirms that L^2(R^n) involves integration over all of R^n, providing an example with three dimensions.

Areas of Agreement / Disagreement

Participants generally agree on the definition of L^2 spaces, but there is some uncertainty regarding the specifics of L^2(R^n) and its implications, indicating that the discussion remains partially unresolved.

Contextual Notes

The discussion highlights the need for clarity on the definitions and properties of L^2 spaces, particularly regarding the integration limits and convergence criteria, which may depend on the context of the functions being considered.

pellman
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Let [tex]H=L^2(R^n)[/tex]

Here H is a Hilbert space, R^n is of course the nth product of the real line. what is L-squared? context is a quantum text for mathematicians.

Later the author uses [tex]H=L^2([0,1])[/tex] in another example.
 
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That makes perfect sense. Thank you!
 
[tex]L^2([0,1])[/tex] means functions whose square integral from 0 to 1 converges, but what is [tex]L^2(R^n)[/tex]? Functions whose square integral from [tex]-\infty[/tex] to [tex]\infty[/tex] converges? Or any sub interval of [tex]R^n[/tex]?
 
It is the integral over all of Rn. For example, if n=3, then [itex]\int_{-\infty}^\infty \int_{-\infty}^\infty \int_{-\infty}^\infty f(x,y,z) dx dy dz[/itex], which is also written in more compact form as [itex]\int_{\textbf{R}^3} f(\textbf{x}) d\textbf{x}[/itex]
 

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