Understanding Joint PDF and Independence in Probability: Solving for P(X+Y<=2)

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SUMMARY

The discussion centers on calculating the probability P(X+Y<=2) using the joint probability density function (PDF) f(x,y) = 1/8x(x-y) for the region defined by 0<=x<=2 and |y|<=x. The teacher's solution involves separating the double integral into two parts, which is valid due to the defined limits of integration. The participant expresses confusion regarding the separation of variables in the integral, questioning the independence of the functions involved. A sketch of the integration regions is recommended for clarity.

PREREQUISITES
  • Understanding of joint probability density functions (PDFs)
  • Familiarity with double integrals in calculus
  • Knowledge of integration limits and regions in the Cartesian plane
  • Basic concepts of probability theory, particularly regarding independence
NEXT STEPS
  • Study the properties of joint probability density functions in detail
  • Learn about the Fubini's Theorem for separating integrals
  • Explore graphical methods for visualizing regions of integration
  • Practice solving problems involving conditional probabilities and independence
USEFUL FOR

Students and professionals in mathematics, particularly those studying probability theory and calculus, as well as educators looking to clarify concepts related to joint PDFs and integration techniques.

cjaylee
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Let the joint PDF of (X,Y) be of the form:
f(x,y) = 1/8x(x-y), 0<=x<=2, |y|<=x
f(x,y) = 0 elsewhere

Find P(X+Y<=2).

The answer that my teacher gave was

P(X+Y<=2)=∫01dx ∫-xx 1/8x(x-y)dy + ∫12dx ∫-x2-x 1/8x(x-y)dy

I do not understand how my teacher could separate the integral like that ∫ dx ∫ dy when the function has both the variable x and y. Shouldn't that be only possible when we can separate the function into 2 separate functions that are independent of each other?

Thanks for the help!
 
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Hint: draw a sketch of the regions of integration in (x,y).
 

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