Understanding Limits: How to Solve Challenging Problems in Calculus

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SUMMARY

This discussion focuses on solving limits in calculus, specifically the limits involving expressions as x approaches infinity. The first limit discussed is lim (x-1)/(sqrt(x²+1)) as x approaches +infinity, where the transformation to g(x)=(x-1)/(sqrt(x²+1)) is clarified by factoring out x. The second limit, sqrt(x^2+x+1)-x, is simplified to x(sqrt(1+1/x+1/x^2)-1) by extracting x from the square root. The participants emphasize that for large x, the constants become insignificant, allowing for straightforward limit evaluation.

PREREQUISITES
  • Understanding of calculus limits
  • Familiarity with algebraic manipulation of expressions
  • Knowledge of square root properties
  • Basic concepts of asymptotic behavior in functions
NEXT STEPS
  • Study the concept of limits at infinity in calculus
  • Learn about algebraic techniques for simplifying expressions
  • Explore the properties of square roots and their limits
  • Investigate online resources for calculus problem-solving, such as Khan Academy or Paul's Online Math Notes
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Students studying calculus, educators teaching limit concepts, and anyone seeking to improve their problem-solving skills in advanced mathematics.

mohlam12
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hello everyone
we've been doing some exercices of limits at class and there are many ones that i didn't understand... and since you don't get that chance to ask your teacher after class in Morcco, I came here for help!
here are two of the tens that i didn't undersatnd:
so to solve this limit:

lim (x-1)/(sqrt(x²+1))
x-> +infinity

you have to go from or each x Є ]-infinity,0[ U ]0, +infinity[
g(x)=(x-1)/(sqrt(x²+1))
...x(1-1/x)
g(x)=-----------------
...|x| sqrt(1+1/x²)

i just want to understand how you go from that first line to th second line !?

and also on this one:

how to go from
[itex]sqrt(x^2+x+1)-x[/itex]
to:
[itex]x(sqrt(1+1/x+1/x^2)-1))[/itex] for each x Є ]0,+infinity[

i really appreciate your help, and also if there is a website that gives you the trucks to solve these kind of limits...thanks again
 
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It's just bringing the x outside of the brackets. Isn't is clear that x(1-1/x) is the same as (x-1) for x/=0? Just expand the brackets.
Same thing with sqrt(x^2+1). You can bring out the x^2 in (x^2+1), giving x^2(1+1/x^2) (valid for x/=0)

But you don't need it to solve the limit. Intuitively you can argue that the -1 in the numerator and the +1 in the denominator are pretty insignificant for large x, so ignoring those you get x/|x|, whose limit is clear.
You can also simply divide top and bottom of the fraction by x.
 

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