Understanding Linear and Nonlinear Operators in Differential Equations

  • Thread starter Thread starter theneedtoknow
  • Start date Start date
  • Tags Tags
    Linear Operator
Click For Summary
The discussion centers on the linearity of operators in differential equations. The operator Lu = du/dx + du/dy + 1 is deemed non-linear because it does not satisfy the linearity condition when combining functions. The equation du/dt - d^2u/dx^2 + 1 = 0 can be rewritten to show it is linear and non-homogeneous, as it can be expressed in the form Lu = -1. The key distinction lies in the conditions for an operator versus an equation to be linear, emphasizing the need to separate constant terms in linear equations. Understanding these differences clarifies the reasoning behind the classification of operators and equations in differential equations.
theneedtoknow
Messages
169
Reaction score
0
These 2 questions are somewhat related:

Is the operator linear: Lu = du/dx + du/dy + 1

I said it's non-linear since L(u+v) = du/dx + dv/dx + du/dy + dv/dy + 1 = Lu + Lv - 1 =/= Lu + Lv

and then:
State whether each of the following equations is nonlinear, linear inhomogeneous, or linear homogeneous.

du/dt - d^2u/dx^2 + 1 = 0
which can be rewritten as du/dt - d^2u/dx^2 = -1
so now we have pretty much the same situation as above, except since it was set to zero, i can just bring the 1 on the other side and the resulting equation is linear and non-homogeneous Lu = -1

So then, is my reasoning for the first question wrong, that the operator (which is almost identical except for the order of derivatives) is actually linear? And then, why is my reasoning wrong?
 
Physics news on Phys.org
theneedtoknow said:
So then, is my reasoning for the first question wrong, that the operator (which is almost identical except for the order of derivatives) is actually linear? And then, why is my reasoning wrong?

Your reasoning is fine, there's just a difference between the conditions for an operator or equation to be linear. Given a linear operator L, there's always an associated linear equation L u = c. If we want to find the linear operator corresponding to a general linear equation, we need to separate any nonzero constant term.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 14 ·
Replies
14
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 8 ·
Replies
8
Views
1K
Replies
21
Views
2K
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
6
Views
2K