Understanding Linear and Nonlinear Operators in Differential Equations

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The discussion centers on the classification of linear and nonlinear operators in differential equations, specifically analyzing the operator defined as Lu = du/dx + du/dy + 1. The conclusion is that this operator is indeed nonlinear due to the presence of the constant term, which violates the linearity condition. Additionally, the equation du/dt - d²u/dx² + 1 = 0 is identified as linear and non-homogeneous when rewritten as du/dt - d²u/dx² = -1. The key takeaway is the importance of recognizing constant terms in determining the linearity of operators and equations.

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theneedtoknow
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These 2 questions are somewhat related:

Is the operator linear: Lu = du/dx + du/dy + 1

I said it's non-linear since L(u+v) = du/dx + dv/dx + du/dy + dv/dy + 1 = Lu + Lv - 1 =/= Lu + Lv

and then:
State whether each of the following equations is nonlinear, linear inhomogeneous, or linear homogeneous.

du/dt - d^2u/dx^2 + 1 = 0
which can be rewritten as du/dt - d^2u/dx^2 = -1
so now we have pretty much the same situation as above, except since it was set to zero, i can just bring the 1 on the other side and the resulting equation is linear and non-homogeneous Lu = -1

So then, is my reasoning for the first question wrong, that the operator (which is almost identical except for the order of derivatives) is actually linear? And then, why is my reasoning wrong?
 
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theneedtoknow said:
So then, is my reasoning for the first question wrong, that the operator (which is almost identical except for the order of derivatives) is actually linear? And then, why is my reasoning wrong?

Your reasoning is fine, there's just a difference between the conditions for an operator or equation to be linear. Given a linear operator L, there's always an associated linear equation L u = c. If we want to find the linear operator corresponding to a general linear equation, we need to separate any nonzero constant term.
 

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