Understanding Logarithm Functions: f(x) = log(100x)

  • Context: High School 
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Discussion Overview

The discussion revolves around the function f(x) = log(100x) and its graphical representation. Participants explore the relationship between different transformations of the logarithmic function, specifically addressing how the function can be interpreted as both a vertical translation and a compression along the x-axis.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant suggests that f(x) = log(100x) can be viewed as compressed by a factor of 1/100 and also rewritten as f(x) = log(x) + 2, indicating a vertical translation up two units.
  • Another participant asserts that it is not both transformations but rather just a vertical translation of the graph of log(x) by two units.
  • A different perspective is offered that highlights the idea of expressing functions in multiple ways, comparing it to how different sums can yield the same total.
  • One participant explains that for any point (x, y) on the graph of y = log(x), there exists a corresponding point (x/100, y) on the graph of f(x) = log(100x), suggesting a compression toward the y-axis.
  • They also note that the same point (x, y) corresponds to (x, y + 2) on the graph of y = log(x) + 2, indicating two different transformations: horizontal compression and vertical translation.

Areas of Agreement / Disagreement

Participants express differing views on whether the transformations represent the same effect or two distinct interpretations. There is no consensus on the relationship between the compression and the vertical translation.

Contextual Notes

Participants discuss the transformations without resolving the underlying assumptions about the nature of logarithmic functions and their graphical representations.

nesan
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We're learning logarithms in school. I asked my teacher this question but she couldn't explain it very well.

For a function such as f(x) = log(100x), base ten of course.

When graphed I could say the graph is "compressed by a factor of 1 / 100"

or

Rewriting f(x) = log(100x) into f(x) = logx + log100 = logx + 2

Now it's f(x) = logx + 2

which is a vertical translation up two units. Why is it both? O.o

What do they have in relation? ]

Please and thank you, just want to understand this. >_<
 
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nesan said:
We're learning logarithms in school. I asked my teacher this question but she couldn't explain it very well.

For a function such as f(x) = log(100x), base ten of course.

When graphed I could say the graph is "compressed by a factor of 1 / 100"

or

Rewriting f(x) = log(100x) into f(x) = logx + log100 = logx + 2

Now it's f(x) = logx + 2

which is a vertical translation up two units. Why is it both? O.o

What do they have in relation? ]

Please and thank you, just want to understand this. >_<


It is not both: it is the same as the graph of log x but translated two units.

DonAntonio
 
DonAntonio said:
It is not both: it is the same as the graph of log x but translated two units.

DonAntonio

Why is it the same?
 
I think you just showed why it's the same. Think of as the number 5. 4 + 1 = 5, 3 + 2 = 5, there can be two ways to write the same number, and in much the same way we can write some functions in multiple ways.
 
If you take any point (x, y) on the graph of y = log(x), you'll see that there is a point (x/100, y) on the graph of f(x) = log(100x), so one way of looking at the graph of f is that it represents a compression toward the y-axis of the graph of y = log(x) by a factor of 100.

On the other hand, the same point (x, y) on the graph of y = log(x) corresponds to the point (x, y + 2) on the graph of y = log(x) + 2, so this version of the function represents a translation up by 2 units.

Although log(100x) ##\equiv## log(x) + 2, we're looking at two different transformations, one in the horizontal direction, and one in the vertical direction. All we are doing is looking at one thing in two different ways.
 

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