- #1
Kumar8434
- 121
- 5
I was thinking about extending the definition of superlogarithms. I think maybe that problem can be solved if we find a function ##f## such that ##fof(x)=log_ax##. Is there some way to find such a function? Maybe the taylor series could be of some help. Or is there some method to find a function such that ##f(f(x))## is at least approximately equal to ##logx##?