Understanding Matrix Multiplication: Solving Homework Problems (5) and (24)

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Homework Statement



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Homework Equations


The Attempt at a Solution



I need help with (5) and (24). For (5), i can find MU and MV but have difficulty in finding MnU and MnV. For (24), i can solve (i) but don't know how to find (A+I)21B.

The answer for (5): MnU=6nu; MnV=9nV...

As for (24) (A+I)21B =
row1: (-3 1 5)
row2: (6 -2 -10)
row3: (3 -1 -5)

Thanks in advance...
 
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vela said:
For #5, try calculating MU and MV. Can you express the results in terms of U and V?

For #24, what did you get for (A+I)B? How is it related to B?

For (5), i get MU=
row1: (6)
row2: (6) and

MV=
(-9)
(18) and i stuck there...For (24), i get (A+I)B=
row1: (-3 1 5)
row2: (6 -2 -10)
row3: (3 -1 -5)
which is same as the answer of (A+I)21B... but i totally don't understand why.. can you help me?

P/S: i managed to find solve (5) already... can you focus on (24)? thanks...
 
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Michael_Light said:
For (5), i get MU=
row1: (6)
row2: (6) and

MV=
(-9)
(18) and i stuck there...
OK, so you have

[tex]MU = \begin{pmatrix} 6 \\ 6 \end{pmatrix} = 6\begin{pmatrix} 1 \\ 1 \end{pmatrix} = 6 U[/tex]

Now if you multiply by M again, you'll get

[tex]M^2 U = M(MU) = M(6U) = 6 (MU) = \dots[/tex]

Can you see how this will work out?
For (24), i get (A+I)B=
row1: (-3 1 5)
row2: (6 -2 -10)
row3: (3 -1 -5)
which is same as the answer of (A+I)21B... but i totally don't understand why.. can you help me?
How is that matrix, (A+I)B, related to B?
 


vela said:
OK, so you have

[tex]MU = \begin{pmatrix} 6 \\ 6 \end{pmatrix} = 6\begin{pmatrix} 1 \\ 1 \end{pmatrix} = 6 U[/tex]

Now if you multiply by M again, you'll get

[tex]M^2 U = M(MU) = M(6U) = 6 (MU) = \dots[/tex]

Can you see how this will work out?

How is that matrix, (A+I)B, related to B?

(A+I)B = B.. okay i understand now... thanks for your help!