Understanding Nabla and its Derivatives in 3D Systems

[f(x)]

Could some one explain what does Nabla operator actually signify ? I understand that the various products with nabla are used to find curl,divergence,gradient in EM, but what does Nabla represent in itself ? A more basic question would be, what does del operator(partial derivative) represent , in a 3d system ?

 

[chroot]

It's a generalization of the derivative operator to multiple dimensions. That's all.

In one dimension, say along the x-axis, the derivative operator looks like this:

$\frac{d}<br /> {{dx}} = \frac{\partial }<br /> {{\partial x}} = \vec i \frac{\partial }<br /> {{\partial x}}$

Since there's only one dimension, the "normal" derivative and partial derivative are the same. Also, there's only way way to take a derivative in one dimension -- along that dimension. Thus, the [itex]\vec i[/tex] is implied.<br /> <br /> In multiple dimensions, say x, y and z, it looks like:<br /> <br /> $\nabla = <br /> \vec i \frac{\partial }<br /> {{\partial x}} + \vec j \frac{\partial }<br /> {{\partial y}} + \vec k \frac{\partial }<br /> {{\partial z}}$<br /> <br /> Same thing, just with more dimensions.<br /> <br /> - Warren[/itex]

 

[arildno]

I would disagree there, chroot.
The one-dimensional analogue of the partial derivative at a point, is the derivative with respect to the elements of some particular sequence converging to that point.

Remember that existence of all partial derivatives does not guarantee differentiability at that point; some similar restriction ought to be provable for "sequential" derivatives in the one-dimensional case.

 

[chroot]

I would disagree there, chroot.
The one-dimensional analogue of the partial derivative at a point, is the derivative with respect to the elements of some particular sequence converging to that point.

So you're saying that del doesn't reduce to the standard one-dimensional derivative d/dx? Can you explain a bit more?

- Warren

 

[f(x)]

What I was referring to was, what does a partial derivative represent (in multiple dimensions) like it represents slope in one dimension co-ordinate system ?

 

[FunkyDwarf]

a gradient vector. the direction in which the function is changing most rapidly, and the magnitude is the amount its changing

 

[neutrino]

a gradient vector. the direction in which the function is changing most rapidly, and the magnitude is the amount its changing

If it acts on a scalar field.

 

[arildno]

So you're saying that del doesn't reduce to the standard one-dimensional derivative d/dx? Can you explain a bit more?

- Warren

Hmm..what I meant is that a partial derivative is the derivative with respect to some proper subset of arguments in the vicinity of the point.
For example along the x-axis (or some line parallell to that) in 2-D, or along the rationals in the 1-D case.

 

[cepheid]

So you're saying that del doesn't reduce to the standard one-dimensional derivative d/dx? Can you explain a bit more?

- Warren

It's still a vector operator...so I would say that in one dimension:

$$\nabla = \hat{x}\frac{d}{dx}$$


I'm sure Arildno's answer was better, but I didn't follow what he was saying.