Understanding Newton's Law of Universal Gravitation

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SUMMARY

The gravitational force acting on the Earth due to the Sun is calculated using Newton's Law of Universal Gravitation, represented by the formula Fg = G(m1m2 / r^2). In this case, the mass of the Earth (m = 5.98 x 10^24 kg) and the mass of the Sun (M = 1.99 x 10^30 kg) are separated by a distance of approximately 150 million kilometers (1.5 x 10^11 m). The gravitational constant G is valued at 6.67 x 10^-11 N m^2/kg^2, leading to a calculated gravitational force of approximately 3.39 x 10^22 N acting on the Earth.

PREREQUISITES
  • Understanding of Newton's Law of Universal Gravitation
  • Familiarity with the gravitational constant (G)
  • Knowledge of mass and distance measurements in physics
  • Ability to perform basic algebraic calculations
NEXT STEPS
  • Study the implications of gravitational force in orbital mechanics
  • Learn about the application of gravitational force in astrophysics
  • Explore variations of the gravitational force in different celestial contexts
  • Investigate the role of gravitational force in satellite motion
USEFUL FOR

Students of physics, educators teaching gravitational concepts, and anyone interested in celestial mechanics and the forces governing planetary motion.

Ecterine
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"Consider the Earth following its nearly circular orbit about the sun. The Earth has a mass mearth=5.98x10^24kg and the sun has mass msu=1.99x10^30kg. They are separated, center to center, by r=93 million miles = 150 million km."

What is the size of the gravitational force acting on the Earth due to the sun?

I'm still setting up the problem...

I think I use the equation Fg=G(m1m2 / r2).

r is the distance between the centers of the two objects.
G is the gravitational constant (so I just leave that as G, right?)

But, is the sun or the Earth m1?
 
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Wait... I just realized how stupid of a question that is. Why do I do this when I'm so tired?
 
K, so now for a better question!

Fg=G(5.98x10^24kg x 1.99x10^30kg / 150,000,000 km)
Fg=G(7.933 x 10^46)Am I on the right track? What do I do with the G?

I know that the gravitational constant G has a value G=6.67x10^-11 N x m2/kg2

If I plug the mass of the sun in as m2 it is...

G=6.67x10^-11 N x 1.99x10^30kg/kg2

but... now I'm lost. :(
 
Fg=(6.67x10^-11 N x 1.99x10^30kg / kg2) (7.933 x 10^46)

:(
 
Ecterine said:
"Consider the Earth following its nearly circular orbit about the sun. The Earth has a mass mearth=5.98x10^24kg and the sun has mass msu=1.99x10^30kg. They are separated, center to center, by r=93 million miles = 150 million km."

What is the size of the gravitational force acting on the Earth due to the sun?

I'm still setting up the problem...

I think I use the equation Fg=G(m1m2 / r2).

r is the distance between the centers of the two objects.
G is the gravitational constant (so I just leave that as G, right?)

But, is the sun or the Earth m1?


The formula for gravitation is F=GMm/R^2. Some people may prefer to rewrite it as F=GM1M2/R^2. Just need to take note that M1 or M is the primary mass and M2 or m is the secondary mass. In this question, the mass of Sun is taken to be M1 or M.

Data used:
Gravitational constant = 6.67x 10^-11 Nm^2kg^-2 = G
Mass of Sun = 1.99x 10^30 kg = M
Mass of Earth = 6.02x 10^24kg = m
Distance between Sun and Earth = 1.5x 10^11m = R

Force acting on Earth by Sun = GMm/R^2
= 3.39X 10^22 N
 
Thank you! :)
 

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