Understanding Pendulum Swing: Physics 11 Help for Equal Height on Right Side

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Homework Help Overview

The discussion revolves around a pendulum problem where the bob is pulled to one side and released, leading to questions about the height it reaches on the opposite side after swinging. The original poster expresses confusion about why the height on the right side is equal to the original height when the pendulum is released.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relevant equations related to kinetic energy (KE), potential energy (PE), and total energy (TE). There are attempts to relate these concepts to the problem at hand, with questions about the characteristics of the pendulum's motion at different points in its swing.

Discussion Status

The discussion is ongoing, with participants providing guidance on the relationships between energy forms and questioning the original poster's understanding of kinetic energy at different points in the pendulum's swing. There is no explicit consensus yet, but there are productive lines of questioning being explored.

Contextual Notes

Participants are navigating the implications of energy conservation in the context of the pendulum's motion, with some uncertainty about the initial conditions and the resulting velocities at key points in the swing.

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Homework Statement



A pendulum bob is pulled sideways to the left. When released, the pendulum string will contact a horizontal rod causing the pendulum to swing in an arc of smaller radius.

the height to which the bob swings on to the right is equal to the original height but i don't understand why-- please help ?


Homework Equations



N/A

The Attempt at a Solution



?
 
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The relevant equations have to do with kinetic energy KE, potential energy PE, and total energy TE.

Show us the equations, and tell us how they could be interpreted to give you your answer.
 
berkeman said:
The relevant equations have to do with kinetic energy KE, potential energy PE, and total energy TE.

Show us the equations, and tell us how they could be interpreted to give you your answer.

KE = 0.5mv^2
PE = mgh
TE = 0.5mv^2 + mgh
= mv^2 + gh
 
roxxyroxx said:
KE = 0.5mv^2
PE = mgh
TE = 0.5mv^2 + mgh
= mv^2 + gh

Good start. (Not sure what you mean by the last line, but the other lines are correct.)

Now, what common characteristic does the ball have when it is first released, and when it stops at the top of its arc after the string contacts the peg? What is the KE in each of those two cases? Answer that, and then answer the whole problem!
 
berkeman said:
Good start. (Not sure what you mean by the last line, but the other lines are correct.)

Now, what common characteristic does the ball have when it is first released, and when it stops at the top of its arc after the string contacts the peg? What is the KE in each of those two cases? Answer that, and then answer the whole problem!

umm I am not 2 sure but:
mgh = 0.5mv^2 + mgh

??
 
roxxyroxx said:
umm I am not 2 sure but:
mgh = 0.5mv^2 + mgh

??

No, how fast is the object moving when FIRST released? How fast when it reaches the top of its arc? What do those velocities tell you about the KE at those two points? Can you then write the equation that answers the original question?
 

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