Rotational Motion of a pendulum

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Homework Help Overview

The discussion revolves around the rotational motion of a pendulum, specifically focusing on determining the rotational speed of the pendulum bob as a function of the changing angle θ. The problem involves variables such as the length of the string, the initial angle, and gravitational acceleration.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the rotational speed and the height of the bob, questioning the presence of certain variables in their equations. There is an exploration of how to simplify the expression for rotational speed and the correct usage of trigonometric functions.

Discussion Status

The discussion is ongoing, with participants attempting to clarify their equations and the feedback received from a software tool. There is a focus on ensuring that the correct variables are included in their final expressions, and some participants suggest simplification strategies.

Contextual Notes

Participants mention receiving hints from a software package regarding the inclusion of specific variables in their answers, indicating potential constraints in how the problem is being interpreted or solved.

xxphysics
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Homework Statement


A pendulum is made of a bob dangling from a lightweight string of length ℓ. The bob is pulled sideways so that the string makes an angle θi with respect to the vertical, then released.

As it swings down, what is the rotational speed of the bob as a function of the changing angle θ? Use the notation l for the length of the string ℓ.
Express your answer in terms of the the variables m, l, θ, θi, and acceleration due to gravity g.

Homework Equations


h = l(cosθ - cosθi)
v=(2gh)^1/2
w = v/l

The Attempt at a Solution


I got w = ((2ghl(cosθ - cosθi))^(1/2))/l , but that was not correct. Are my equations wrong? Thanks
 
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xxphysics said:
I got w = ((2ghl(cosθ - cosθi))^(1/2))/l
How come there is still an h in there?
 
haruspex said:
How come there is still an h in there?
oh sorry ignore that. I entered it without it
 
xxphysics said:
oh sorry ignore that. I entered it without it
Then your answer looks ok to me. Do you know what the official answer is? Or do you enter it into a software package that simply says yes or no? If the second, maybe you need to simplify it a bit by cancellation, leaving l in the denominator only.
 
haruspex said:
Then your answer looks ok to me. Do you know what the official answer is? Or do you enter it into a software package that simply says yes or no? If the second, maybe you need to simplify it a bit by cancellation, leaving l in the denominator only.
I enter it on the computer. It gave me the hint "The correct answer involves the variable \texttip{\theta _}{theta_}, which was not part of your answer.", but I guess my computer isn't able to read that portion of the tip ? Not sure, but thank you
 
haruspex said:
Then your answer looks ok to me. Do you know what the official answer is? Or do you enter it into a software package that simply says yes or no? If the second, maybe you need to simplify it a bit by cancellation, leaving l in the denominator only.
How would you simplify it further since for the numerator the square root needs to be taken ?
 
xxphysics said:
I enter it on the computer. It gave me the hint "The correct answer involves the variable \texttip{\theta _}{theta_}, which was not part of your answer.", but I guess my computer isn't able to read that portion of the tip ? Not sure, but thank you
Sounds like it needs you to enter it as cos(θ) etc., not cosθ. Or maybe you did.
xxphysics said:
How would you simplify it further since for the numerator the square root needs to be taken ?
√x/x=1/√x
 

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