Understanding Perfectly Black Bodies

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Discussion Overview

The discussion centers around the concept of a perfectly black body in physics, exploring its definition, properties, and the mechanisms of absorption and emission of radiation. Participants delve into the theoretical aspects of black bodies, their behavior when heated, and the implications of atomic energy levels in relation to radiation emission.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant defines a black body as an object that absorbs all wavelengths of radiation and reflects none, questioning how it emits radiation when heated.
  • Another participant describes a hot cavity as a close approximation to a perfect black body, noting that black velvet serves as a room temperature approximation.
  • Several participants express confusion about the relationship between heating a body and its emission of radiation, particularly regarding electron transitions and energy levels.
  • It is mentioned that a black body is a hypothetical construct and does not exist in reality.
  • One participant clarifies that black bodies emit radiation based on thermal equilibrium and that all bodies above absolute zero emit radiant energy, depending on their surroundings.

Areas of Agreement / Disagreement

Participants exhibit a mix of agreement and confusion regarding the mechanisms of radiation emission and the nature of black bodies. While some points are clarified, the discussion remains unresolved on certain aspects, particularly the implications of atomic energy levels in relation to black body behavior.

Contextual Notes

There are limitations in the discussion regarding the assumptions about atomic energy levels and the nature of black bodies, as well as the dependence on definitions of thermal radiation and equilibrium.

EF17xx
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Hi! I'm trying to understand a perfectly black body. So the definition I have found is that

a black body is one that absorbs radiation of ALL wavelengths and reflects NONE. Therefore it appears black at low temperatures. And when heated it emits radiation of all wavelengths making it appear very bright yellow orange.

So now I'm trying to understand HOW and WHY.

When atoms of a substance absorb energy for example in the form of radiation, the radiation must have an energy that corresponds to the energy required for an electron to move between its energy levels. Jump to a higher energy level. And if the atom receives energy from radiation of different wavelengths it will reflect the ones that do not have the corresponding energy. In the case of a perfect blackbody this is not the case. It absorbs ALL.
What I don't understand is that when the body is heated, it receives energy (temperature is a measure of kinetic energy of particles) so why would it emit radiation. since when it emits the electrons jump to a LOWER energy level?

Also what makes a black body a black body because wouldn't that mean it consists of all the diffrent elements in the world to be able to absorb energy of all wavelengths and each element has atoms with different energy levels which always have to correspond to the energy that is being targeted at them.And I'm just wondering if someone could give me feedback on my thinking and to what extent it is correct and whether there is any additional information that could help me understand.
 
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A close approximation to a perfect black body is a hot cavity with a small through hole in one wall. The radiant energy inside the cavity is reflected internally with little chance of escape. This is a way to optically measure the temperature of a body. Drill a small hole in the hot body and observe the emitted radiation. The room temperature approximation to a black body is black velvet. The radiation upon black velvet is nearly perfectly absorbed. Don't confuse the electron transitions in gases with solid bodies.
 
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EF17xx said:
What I don't understand is that when the body is heated, it receives energy (temperature is a measure of kinetic energy of particles) so why would it emit radiation. since when it emits the electrons jump to a LOWER energy level?

because it IS HEATED ... it will emit thermal electromagnetic radiation. And if heated enough, it will emit visible light electromagnetic radiation

Yes, that's basically correct what is the problem there ?


EF17xx said:
Also what makes a black body a black body because wouldn't that mean it consists of all the diffrent elements in the world to be able to absorb energy of all wavelengths and each element has atoms with different energy levels which always have to correspond to the energy that is being targeted at them.

you do realize that a "black body" is hypothetical ? ... it cannot really exist
 
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First of all, blackbodies are not absorbing and emitting based on available atomic energy levels.

EF17xx said:
What I don't understand is that when the body is heated, it receives energy (temperature is a measure of kinetic energy of particles) so why would it emit radiation.
Any blackbody emits radiation. When it is heated it emits more radiation. If you have a blackbody in equilibrium with its surroundings and you then heat it up, it will start emitting more radiation to get rid of the excess energy that you added by heating it until it is in equilibrium with the surroundings again. This is in perfect accordance with that heat flows from a warmer system to a colder one.
 
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Actually anybody whose temperature is above zero K emits radiant energy. Whether it is a net receiver or emitter depends on the temperature of its surroundings.
 
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Thank you! I didn't think about the energy equilibrium but knowing that it makes a lot more sense.
 

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