Understanding Probability Density Functions for Beginners

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Probability density functions (PDFs) represent the likelihood of a random variable falling within a specific range, with the area under the curve indicating the probability of occurrence. The function f(x) has units of "probability per unit length," meaning that f(x) alone does not represent probability, but rather a density that requires integration over an interval (dx) to yield a probability value. The relationship between f(x) and dx is analogous to physical density, where integrating density over a volume gives mass. The discussion highlights the importance of defining a sample space and associated measures to fully understand probabilities. Clarification on the histogram's role and the variable c is sought, emphasizing the need for more context in the explanation.
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hello all!

i am wondering about probability density functions. i know the area under a pdf gives the probability of an event, but i am having a difficult time seeing this. specifically, given a pdf we have ##\int_a^b f(x) dx## as the probability of an occurrence from ##[a,b]##. what are the units of ##f(x)##? why exactly is ##f \times dx## the probability, rather than just ##f## itself?

please illustrate with a histogram if you can. thanks!
 
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i should add, in the text I'm using we are given that, if ##H(c, \Delta c, N)## where ##\Delta c## is the slot width, ##N## is the number of realizations of the random variable. evidently $$B(c) := \lim_ {\substack{\Delta c \to 0 \\ N \to \infty}}\frac{H(c, \Delta c, N)}{\Delta c}$$

where ##B(c)## is a pdf. can someone help explain this? nothing was really said about ##c## or ##H## other than ##H## is the histogram. i assume ##c## is a random variable?
 
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joshmccraney said:
what are the units of ##f(x)##? why exactly is ##f \times dx## the probability, rather than just ##f## itself?

Think of "density" in terms of physical density - for example, let f(x) be the mass density of a rod given in terms of kilograms per meter at the point x. To find the mass of a rod between two points, you'd do an integration. The value of f(x_0) at the point x_0 is some value of density, not a value indicating mass.

You could say that the "units" of a pdf are "probability per unit length" (or "per unit area" etc.) , but I don't know if anyone has ever worked out a good way for abbreviating all the information that goes along with "probability" in the same system we use for units in physics. To speak of "the probability" of an event unambiguously, you have to define a "sample space" and an algebra of sets of events and a measure defined on that algebra. If we say that a particular formula "is a pdf" then we convey a lot of mathematical conventions with that short phrase. As far as I know, in physics "probability" is a "dimensionless" quantity. From that point of view, the "units" of a pdf are 1 over the unit of measure used on the sample space. .
 
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joshmccraney said:
we are given that, if ##H(c, \Delta c, N)##

You didn't say what H is. You only defined its arguments.
 
thanks for the reply! yea, tho author of the text on states that ##H## is a histogram. nothing more is stated that i haven't already listed...it's pretty annoying.
 
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