Understanding PV Diagrams: Analyzing Work, Heat, and Temperature Changes

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Homework Help Overview

The discussion revolves around understanding PV diagrams, specifically analyzing the relationships between work, heat, and temperature changes in thermodynamic processes. Participants are exploring the implications of different paths on work done and heat transfer, as well as the relationship between internal energy and temperature.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants discuss the significance of the area under the path in PV diagrams to determine work done. There is an exploration of the relationship between internal energy changes and heat transfer, with some questioning the validity of certain statements regarding paths and their implications for heat and work. Others raise questions about the relationship between internal energy and temperature, particularly in the context of ideal gases.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's statements and clarifying misconceptions. Some guidance has been offered regarding the relationships between variables, but there is still uncertainty about specific assumptions and interpretations of the PV diagram.

Contextual Notes

Participants are navigating potential misunderstandings about the paths in the PV diagram and the implications of internal energy changes. There is also a focus on the relationship between pressure, volume, and temperature, particularly in the context of ideal gas behavior.

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Homework Statement


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Homework Equations

The Attempt at a Solution


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I was wondering if the answer is all statements are true. I want to know if my reasons are correct:

1) the work done by the system is greatest along path 1 because work done is equal to the area under the path. The path under 1 is clearly largest of the two other paths.

2) if Ub > Ua , then Q is greatest along path b. Since the delta U for the other paths are equal to that of path 1, the equation becomes Q=W for all paths as delta U can be ignored in comparison. Q is largest for path 1 because W is largest.

3)Heat is absorbed by the system because Q is positive since deltaU is positive. When Q is positive, this means that heat is added to the system (same as heat aborbed by the system).
 

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It all looks good to me except for the first part of your statement 2 where you said
lc99 said:
2) if Ub > Ua , then Q is greatest along path b.
There is no path b. But the rest of your statement 2 appears to be correct. You are right that ΔU is the same for all paths, so you don't need to worry about ΔU when comparing paths for Q. But, still, I wouldn't write Q = W.
 
TSny said:
It all looks good to me except for the first part of your statement 2 where you said
There is no path b. But the rest of your statement 2 is right. Also, you are right that ΔU is the same for all paths, so you don't need to worry about ΔU when comparing paths for Q. But, still, I wouldn't write Q = W.
oops , you are right. i meant path 1. Also, I guess it was easier to understand it if i wrote Q=W.

Also, regardless of statement 2, it's true that change in U is the same for all of them, but I am unsure if change is U increases? I would think U increases. Is there any information that would say so?
 
lc99 said:
Also, regardless of statement 2, it's true that change in U is the same for all of them, but I am unsure if change is U increases? I would think U increases. Is there any information that would say so?
Consider the product PV for the initial and final states. Which state has the higher value for PV? What does that tell you about the temperatures for the initial and final states? For an ideal gas, how is U related to temperature?
 
TSny said:
Consider the product PV for the initial and final states. Which state has the higher value for PV? What does that tell you about the temperatures for the initial and final states? For an ideal gas, how is U related to temperature?
Ahh. That makes sense. U is higher in the final state because of the temperature increase due to PV relationship.

Also, is it also correct to say that temperature increases because isotherms tend to be up and into the graph which represent higher temperatures?
 
lc99 said:
Also, is it also correct to say that temperature increases because isotherms tend to be up and into the graph which represent higher temperatures?
Yes.
 

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