Understanding Quantum Wave Packets: How to Derive the Schrodinger Equation

  • Thread starter Thread starter silimay
  • Start date Start date
  • Tags Tags
    Quantum
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
silimay
Messages
25
Reaction score
0
Sorry... my message got posted by mistake before I started typing. Here is what I was going to say:

I'm having a problem just understanding something from my quantum book. They're deriving something to do with a wave packet with the Schrödinger equation, and they have the equation of a wave packet at time t = 0:

[tex]\psi(x,0) = \int_{- \infty}^{+ \infty} dk A(k) e^{i(kx)[/tex]

where [tex]A(k) = e^{- \alpha (k - k_o)^2 / 2}[/tex]

They change variables to [tex]q' = k - k_o[/tex] and then they get

[tex]\psi(x,0) = e^{i k_o x} e^{- x^2 / {2 \alpha}} \int_{- \infty}^{+ \infty} dq' e^{- \alpha {q'}^2 / 2}[/tex]

I don't understand how they got that (specifically, the [tex]e^{-x^2 / {2 \alpha}}[/tex] term).
 
Last edited:
Physics news on Phys.org
They did the substitution and then completed the square in q' in the integral and brought the non-square stuff outside the integral. Finally they shifted q'->q'-ix/alpha.
 
Last edited:
Thanks so much for your help =) =) =) I understand it now.