Understanding SHM Equations: Solving Two Equations and Identifying Mistakes

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SUMMARY

The discussion focuses on solving simple harmonic motion (SHM) equations and identifying mistakes in the interpretation of amplitude and angular frequency. The equations presented include y = 2Acos2ωt and y = A(sinωt + √3cosωt), leading to the conclusion that the amplitude is 2A and the angular frequency is ω. The participant concludes that the maximum speed is consistent across both equations, affirming that Option 3 is correct despite the provided answer being Option 2. The mistake identified is the misinterpretation of the maximum position in relation to the origin.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM) principles
  • Familiarity with trigonometric identities and their applications in physics
  • Knowledge of angular frequency and amplitude in oscillatory motion
  • Ability to analyze and interpret mathematical equations related to motion
NEXT STEPS
  • Review the derivation of SHM equations and their physical implications
  • Study the relationship between amplitude, angular frequency, and maximum speed in SHM
  • Learn about the graphical representation of SHM and its characteristics
  • Explore common mistakes in interpreting SHM problems and how to avoid them
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators looking to clarify common misconceptions in SHM equations.

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Homework Statement


2Shm.jpg


Homework Equations

The Attempt at a Solution



y = 2Acos2ωt = A(1+cos2ωt)

y-A = Acos2ωt . This is SHM with origin at y = A i.e at the maximum position .

Is that correct ?

Amplitude is A and angular frequency is 2ω .

y= A(sinωt+√3cosωt) = 2Asin(ωt+π/3)

Amplitude is 2A and angular frequency is ω .

Maximum speed is product of amplitude and angular frequency .

Product is same in both the cases .

This makes Option 3) correct .

But given answer is option 2) .

What is the mistake ?
 

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Jahnavi said:
This is SHM with origin at x = A i.e at the maximum position .
Origin is x = A, yes, but it is definitely not the maximum position of this SHM.

Jahnavi said:
This makes Option 3) correct .

But given answer is option 2) .

What is the mistake ?
Option C is correct.
 
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Thanks !
 

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