Why is my thinking incorrect? -- Block and spring driven by a motor

Click For Summary

Homework Help Overview

The discussion revolves around an oscillator consisting of a block attached to a spring, with given values for position, velocity, and acceleration. Participants are exploring the relationships between these quantities and their implications for determining frequency, mass, and amplitude.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the validity of using the equation v=ωx at arbitrary times, discussing the distinction between instantaneous values and those at maximum amplitude. They are also examining the applicability of the acceleration formula a=(-ω²)x in the context of changing values over time.

Discussion Status

The conversation is ongoing, with participants clarifying misunderstandings about the equations of motion for oscillating systems. Some have provided insights into the nature of the equations and their applicability, while others are still grappling with the implications of the changing values of velocity and acceleration.

Contextual Notes

There is an emphasis on the need for clarity regarding the assumptions made about the motion of the oscillator, particularly concerning the time-dependence of velocity and acceleration. Participants are also encouraged to share their results as part of the collaborative learning process.

ryley
Messages
20
Reaction score
2

Homework Statement


An oscillator consists of a block attached to a spring (k=400n/m). At some time t, the position (from equilibrium), velocity, and acceleration of the block are x= .100m, v= -13.6m/s, a= -123m/s^2.
What is the frequency? mass of block? amplitude.

Homework Equations


position function, velocity function, acceleration function

3.The attempt at a solution
The problem I'm having with this question is with part a. I understand the solution I looked up but what I don't understand is why I can solve for ω by rearranging v=ωx for ω=v/x? I know to use the acceleration formula a=(-ω^2)x and ω=√(a/x).
Is it that the velocity mentioned in the question is not the same form of velocity used in the velocity formula for SHM?

Any help would be much appreciated!
 
Last edited:
Physics news on Phys.org
##v(t)=\omega x(t)## is not true for all times t. It is true only as an equation between amplitudes that is ##v_0=\omega x_0##
On the other hand, ##a(t)=-\omega^2 x(t)## is true for all times t. So that's the equation to use to find ##\omega## since our data for x, v, and a are at some random time t.
 
Thanks for the response! I guess what I'm still confused about though is that an object that is oscillating has a velocity and acceleration value that are always changing depending on time. So if at some time t acceleration is 123m/s^2 at another time it would be different as well so I don't understand how we can assume acceleration in this problem is true at all times.
 
Delta2 said:
##v(t)=\omega x(t)## is not true for all times t. It is true only as an equation between amplitudes that is ##v_0=\omega x_0##
On the other hand, ##a(t)=-\omega^2 x(t)## is true for all times t. So that's the equation to use to find ##\omega## since our data for x, v, and a are at some random time t.

Thanks for the response! I guess what I'm still confused about though is that an object that is oscillating has a velocity and acceleration value that are always changing depending on time. So if at some time t acceleration is 123m/s^2 at another time it would be different as well so I don't understand how we can assume acceleration in this problem is true at all times.
 
I didn't mean that acceleration is constant at all times, I meant that this equation
##a(t)=-\omega^2x(t)## is true at all times, this equation involves ##a(t)## and ##x(t)## as functions of time t, so they change when time t changes.
 
  • Like
Likes   Reactions: ryley
Delta2 said:
I didn't mean that acceleration is constant at all times, I meant that this equation
##a(t)=-\omega^2x(t)## is true at all times, this equation involves ##a(t)## and ##x(t)## as functions of time t, so they change when time t changes.
Oh okay that makes more sense! Thanks so much again!
 
ryley said:
Oh okay that makes more sense! Thanks so much again!
Hello @ryley .
A belated ... :welcome:

As a Homework Helper, it's good to see the final results/solutions obtained by those we help. After all, we are volunteers and receive no pay for the help we give.

What are the results you got for the questions you were to answer?
ryley said:
What is the frequency? mass of block? amplitude?.
 
  • Like
Likes   Reactions: ryley
SammyS said:
Hello @ryley .
A belated ... :welcome:

As a Homework Helper, it's good to see the final results/solutions obtained by those we help. After all, we are volunteers and receive no pay for the help we give.

What are the results you got for the questions you were to answer?
Oh sure thing, Ill be home tomorrow and will upload the solutions I have!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
Replies
29
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
5
Views
4K
  • · Replies 8 ·
Replies
8
Views
5K
Replies
5
Views
2K