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i mean to ask that if we make a free body diagram of the space elevator then where and in which direction forces will act on it.

and why that forces will act as they are doing

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- Thread starter RohitRmB
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In summary: Earth (gravitational force will be higher than centrifugal force), and on the upward side will be away from Earth (centrifugal force will be higher than gravitational force). Therefore, the forces will be pulling in opposite directions by an equal quantity. You must, of course, get the sign correct when you add them.

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i mean to ask that if we make a free body diagram of the space elevator then where and in which direction forces will act on it.

and why that forces will act as they are doing

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Non-rotating: Downward forces from gravity everywhere, towards the center of earth. An additional part is tension in the cable, which is a bit hard to show in a sketch as it is relevant everywhere. It has its largest value at geostationary orbit. Below, the reduction of tension (with lower altitude) gives a net force upwards for every cable element, and above, the reduction of tension (with higher altitude) gives a net force downwards for every cable element.

Every cable element with mass m gets a total force of mωr^2 inwards, keeping in a circular orbit.

Rotating: Downward forces from gravity everywhere, towards the center of earth. Additional, every mass element gets a force of mωr^2 outwards, and tension as described above. The sum of all forces is 0 for all mass elements.

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It's not that simple. The stress at each point is not just a function of the mass below it, but also of the angular velocity:grahamgk said:

http://en.wikipedia.org/wiki/Space_elevator#Cable_section

And above the geosynchronous level, there is stress too.

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If you assume a motionless cable (in the rotating frame) or a uniformly rotating cable (in the inertial frame) then it is sufficient to integrate the force contributed by each mass element from one end of the cable up to the chosen point.grahamgk said:

It does not matter which end you integrate from. The magnitude of the calculated force will be identical either way. The signs of the calculated forces will be opposite, of course.

If you were to integrate both "below and above" and then add the results together you'd be sure to get the wrong answer, either by double-dipping (with a sign error) or cancellation (without the sign error).

The wording of a counterweight "just barely pulling the ribbon taut" seems off. The ribbon is not going to go slack without a counterweight. It is taut under centrifugal force. The counterweight is there so that the ribbon's orbit neither falls from nor flies away from a circular orbit.

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jbriggs444 said:If you were to integrate both "below and above" and then add the results together you'd be sure to get the wrong answer, either by double-dipping (with a sign error) or cancellation (without the sign error).

The wording of a counterweight "just barely pulling the ribbon taut" seems off. The ribbon is not going to go slack without a counterweight. It is taut under centrifugal force. The counterweight is there so that the ribbon's orbit neither falls from nor flies away from a circular orbit.

If you use the point on the ribbon at the geosynchronous level as an example, the net force on the downward side will be toward Earth (gravitational force will be higher than centrifugal force), and on the upward side will be away from Earth (centrifugal force will be higher than gravitational force). Therefore, the forces will be pulling in opposite directions by an equal quantity. You must, of course, get the sign correct when you add them.

The ribbon is only taut from centrifugal force when there is a counterweight or an incredibly long ribbon past the geosynchronous level. Without the counterweight (or the incredibly long ribbon), the net forces for the entire ribbon will be toward Earth and the ribbon will fall to Earth.

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grahamgk said:If you use the point on the ribbon at the geosynchronous level as an example, the net force on the downward side will be toward Earth (gravitational force will be higher than centrifugal force), and on the upward side will be away from Earth (centrifugal force will be higher than gravitational force). Therefore, the forces will be pulling in opposite directions by an equal quantity. You must, of course, get the sign correct when you add them.

When you add them, the result should be zero. If your goal was to compute the tension in the ribbon then adding upward force to downward force is just plain wrong.

Suppose that you have two teams playing tug-of-war, each pulling on a rope. Team A is pulling with 1000 pounds-force to the left. Team B is pulling with 1000 pounds-force to the right.

Is the tension on the rope:

A. 2000 pounds-force

B. 1000 pounds-force

C. 0 pounds-force

D. None of the above

My answer is B. It seems that your answer is A.

The ribbon is only taut from centrifugal force when there is a counterweight or an incredibly long ribbon past the geosynchronous level. Without the counterweight (or the incredibly long ribbon), the net forces for the entire ribbon will be toward Earth and the ribbon will fall to Earth.

The ribbon is taut regardless. It is rotating and not massless. To a first approximation, the ribbon will have an elliptical orbit such that [portions of] the ribbon may or may not intersect with the surface of the earth. Whether the ribbon falls "to the Earth" will depend on that detail.

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jbriggs444 said:When you add them, the result should be zero. If your goal was to compute the tension in the ribbon then adding upward force to downward force is just plain wrong.

Suppose that you have two teams playing tug-of-war, each pulling on a rope. Team A is pulling with 1000 pounds-force to the left. Team B is pulling with 1000 pounds-force to the right.

Is the tension on the rope:

A. 2000 pounds-force

B. 1000 pounds-force

C. 0 pounds-force

D. None of the above

My answer is B. It seems that your answer is A.

I agree with your analogy and that the tension in the rope would be 1000 pounds-force, and, therefore, I agree that it is not correct to add the opposing forces at the geosynchronous point for the space elevator ribbon. The tension on the space elevator ribbon at the geosynchronous level (or any point below that point) will be equal to the net force below that point. The closer to the Earth, the lower the tension.

The ribbon is taut regardless. It is rotating and not massless. To a first approximation, the ribbon will have an elliptical orbit such that [portions of] the ribbon may or may not intersect with the surface of the earth. Whether the ribbon falls "to the Earth" will depend on that detail.

When I used the word "taut," I meant from the point the ribbon is connected to the Earth and upward. If the net forces are downward at the geosynchronous level, the entire ribbon will gradually be pulled toward the Earth until it completely falls to the ground, becoming slack at points close to the Earth as it falls. For example, if the counterweight of a space elevator were released from the ribbon, the net forces at the geosynchronous level would change from being net zero or upward to being downward and the ribbon would be pulled toward the Earth.

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grahamgk said:When I used the word "taut," I meant from the point the ribbon is connected to the Earth and upward.

Ahh, that makes sense. I was automatically assuming that the tension at the bottom end of the elevator would be zero (and even thinking in terms of an unanchored elevator) and you were carefully arranging things so that the tension at the anchor would be zero.

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An additional complexity in the analysis for a real space elevator ribbon, which is usually incorporated into conceptual designs, is that the ribbon would be tapered. Since the tension decreases going from the geosynchronous level downward, the ribbon does not need to be as wide either. This reduces the mass, and downward gravitational force, for the entire ribbon, and reduces the width (and mass) all along it. This tapering is also applied to the ribbon section between the geosynchronous level and the counterweight.

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grahamgk said:

An additional complexity in the analysis for a real space elevator ribbon, which is usually incorporated into conceptual designs, is that the ribbon would be tapered. Since the tension decreases going from the geosynchronous level downward, the ribbon does not need to be as wide either. This reduces the mass, and downward gravitational force, for the entire ribbon, and reduces the width (and mass) all along it. This tapering is also applied to the ribbon section between the geosynchronous level and the counterweight.

I would think in a real space elevator the bottom end would be under compression instead of tension. It would be built like a tower supporting its weight from the ground up. There would be a transition section which would be under minimal tension or compression, and an upper section under tension as you were supposing. Building the elevator this way it is supported from both ends, allowing for a stronger structure.

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Tension is way easier to handle - you do not need additional support structures everywhere, and materials can handle more tension than compression forces.

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However, a Lunar Space Elevator could be built using existing materials, because of the moon's lower gravity. LiftPort Group is currently pursuing this. http://liftport.com/

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If you build something to 1km high then the weight of the top floor will be transferred down to the foundations. But if you build it to 36km, the weight of the top floor is entirely compensated for by the centripetal force keeping it in circular motion. All floors above this floor then exhibit a centrifugal force upwards, which, when transferred down through the building, acts to nullify the weight of one of the floors below 36km. So theoretically could we not keep building until we reach a point where the upward centrifugal forces of all the floors above 36km serve to cumulatively nullify the weights of all the floors below 36km?

If we stop at this point, should the tension at the point of contact with the Earth not be zero? And then the only limiting factor is the tensile strength of the cable at some point (maybe 36km?) where it is maximised?

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MikeyW said:

If you build something to 1km high then the weight of the top floor will be transferred down to the foundations. But if you build it to 36km, the weight of the top floor is entirely compensated for by the centripetal force keeping it in circular motion. All floors above this floor then exhibit a centrifugal force upwards, which, when transferred down through the building, acts to nullify the weight of one of the floors below 36km. So theoretically could we not keep building until we reach a point where the upward centrifugal forces of all the floors above 36km serve to cumulatively nullify the weights of all the floors below 36km?

If we stop at this point, should the tension at the point of contact with the Earth not be zero? And then the only limiting factor is the tensile strength of the cable at some point (maybe 36km?) where it is maximised?

Yes, all of this is correct, except that it's 36,000 km, not 36 km.

A space elevator is a proposed system for transportation from the surface of the Earth to outer space. It would consist of a cable anchored to the Earth's surface and extending into space, with a counterweight at the other end to keep the cable taut. The idea is that vehicles or payloads could travel up and down the cable using electrically-powered climbers.

The main source of stress on a space elevator would be the weight of the cable itself. As the cable extends from the Earth's surface into space, it would experience an increasing gravitational pull, which would put tension on the cable. This tension would need to be carefully managed to prevent the cable from breaking.

Currently, there is no known material that could withstand the stresses of a space elevator. However, some proposed materials include carbon nanotubes, graphene, and diamond nanothreads. These materials are incredibly strong, lightweight, and have high tensile strength, making them potential candidates for use in a space elevator.

There are a few proposed ways to anchor a space elevator to the Earth's surface. One idea is to use a floating platform in the ocean, which would be stabilized by underwater cables. Another option is to use a tall tower, similar to a traditional elevator, but with much stronger and more stable foundations. Alternatively, the cable could be anchored to a mountain or other natural feature on the Earth's surface.

A space elevator could revolutionize space travel and open up new opportunities for exploration and research. It would greatly reduce the cost of launching payloads into space, as well as the risk and environmental impact of traditional rocket launches. It could also make it possible for larger and more complex spacecraft to be built in space, as they would not need to withstand the forces of Earth's gravity during launch.

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