MHB Understanding the Basics of Social Media Marketing

[Albert1]

View attachment 3058

 

[kaliprasad]

Spoiler

let AB = y and AC= x

$y^2-x^2=n^2$
or$(y+x)(y-x) = n^2$
as n is prime

$y+x = n^2$ and $y-x=1$ as they cannot be both n

so $AB+AC = n^2$ and $AB+AC+BC=n^2+n$

 

[Albert1]

Spoiler

let AB = y and AC= x

$y^2-x^2=n^2$
or$(y+x)(y-x) = n^2$
as n is prime

$y+x = n^2$ and $y-x=1$ as they cannot be both n

so $AB+AC = n^2$ and $AB+AC+BC=n^2+n$

very nice!