MHB Understanding the Chinese Remainder Theorem for $\mathbb{Z}^{\times} _{20}$

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The discussion focuses on demonstrating that the group of units $\mathbb{Z}^{\times}_{20}$ is isomorphic to the product $\mathbb{Z}_{2} \times \mathbb{Z}_{4}$. Participants reference the Chinese Remainder Theorem, which states that $\mathbb{Z}^{\times}_{20} \simeq \mathbb{Z}^{\times}_{2^2} \times \mathbb{Z}^{\times}_{5}$. There is a consensus that $\mathbb{Z}^{\times}_{2^2}$ is isomorphic to $\mathbb{Z}_{2}$, leading to the conclusion that $\mathbb{Z}^{\times}_{20} \simeq \mathbb{Z}_{2} \times \mathbb{Z}^{\times}_{5}$. The discussion also touches on the condition for isomorphism based on the relationship between group order and Euler's totient function.
NoName3
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How do I show that $\mathbb{Z}^{\times} _{20} ≅ \mathbb{Z}_{2} \times \mathbb{Z}_{4}$?

I read that the chinese remainder theorem is the way to go but there are many versions and I can't find the right one. Most versions that I have found are statements between multiplicative groups, not from multiplicative group to additive product like we have here.
 
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NoName said:
How do I show that $\mathbb{Z}^{\times} _{20} ≅ \mathbb{Z}_{2} \times \mathbb{Z}_{4}$?

I read that the chinese remainder theorem is the way to go but there are many versions and I can't find the right one. Most versions that I have found are statements between multiplicative groups, not from multiplicative group to additive product like we have here.

Hi NN!

Indeed, the Chinese Remainder Theorem says that:
$$\mathbb Z^\times_{20} \simeq \mathbb Z^\times_{2^2} \times \mathbb Z^\times_{5}$$
Is $\mathbb Z^\times_{2^2}$ isomorphic to $\mathbb{Z}_{2}$? (Wondering)
 
I like Serena said:
Hi NN!

Indeed, the Chinese Remainder Theorem says that:
$$\mathbb Z^\times_{20} \simeq \mathbb Z^\times_{2^2} \times \mathbb Z^\times_{5}$$
Is $\mathbb Z^\times_{2^2}$ isomorphic to $\mathbb{Z}_{2}$? (Wondering)
Hi, I like Serena,

Thanks for the reply. Yes, I think they're isomorphic.
 
NoName said:
Hi, I like Serena,

Thanks for the reply. Yes, I think they're isomorphic.

So?

Oh, and why do you think they are isomorphic? (Wondering)
 
I like Serena said:
So?

Oh, and why do you think they are isomorphic? (Wondering)
So $\mathbb Z^{\times}_{20} \simeq \mathbb Z_{2} \times \mathbb Z^\times_{5}$? As for why, two groups of the same order are isomorphic if $\gcd(n, \phi(n)) = 1$. This satisfies that.
 
NoName said:
So $\mathbb Z^{\times}_{20} \simeq \mathbb Z_{2} \times \mathbb Z^\times_{5}$?

Yep!

As for why, two groups of the same order are isomorphic if $\gcd(n, \phi(n)) = 1$. This satisfies that.

Huh? :confused:
I didn't know that yet, but it seems to be true.
Can you provide a reference?
 
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