Understanding the Finite Value of ##\zeta(-1)##

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Discussion Overview

The discussion revolves around the finite value of the Riemann zeta function at ##\zeta(-1)##, specifically addressing the apparent contradiction between the infinite series ##1 + 2 + 3 + 4 + 5 + ...## and the result ##\zeta(-1) = -\frac{1}{12}##. Participants explore the implications of this result and the concept of analytic continuation in the context of complex analysis.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant states that ##\zeta(-1) = -\frac{1}{12}## and questions how this finite result can arise from the infinite series of positive integers.
  • Another participant provides a link to an article that discusses the computation of this value, suggesting that there are resources available for further understanding.
  • Several participants express confusion regarding the convergence of the series ##\sum^{\infty}_{n=1}\frac{1}{n^{\alpha}}##, noting that it converges only for ##\alpha > 1##, and question how ##\zeta(-1)## is defined in the complex plane.
  • One participant introduces the concept of analytic continuation as a means of understanding the value of ##\zeta(-1)##, referencing external sources for further clarification.

Areas of Agreement / Disagreement

Participants generally express confusion and seek clarification on the relationship between the infinite series and the value of ##\zeta(-1)##. There are multiple competing views regarding the interpretation of this result and the role of analytic continuation, indicating that the discussion remains unresolved.

Contextual Notes

Participants highlight limitations in understanding the convergence of the series and the definitions involved in the analytic continuation of the zeta function. There is an acknowledgment of the need for further exploration of these concepts.

LagrangeEuler
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\sum^{\infty}_{n=1}\frac{1}{n^{\alpha}}=\zeta(\alpha)
For ##\alpha=-1##

##\zeta(-1)=-\frac{1}{12}##
I do not see any difference between sum
##1+2+3+4+5+...##
and ##\zeta(-1)##. How the second one is finite and how we get negative result when all numbers which we add are positive. Thanks for the answer.
 
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I do not understand this so well. So
Series
##\sum^{\infty}_{n=1}\frac{1}{n^{\alpha}}## converges for ##\alpha>1##. Why in complex plane ##\zeta(-1)## makes sence?
 
LagrangeEuler said:
I do not understand this so well. So
Series
##\sum^{\infty}_{n=1}\frac{1}{n^{\alpha}}## converges for ##\alpha>1##. Why in complex plane ##\zeta(-1)## makes sence?
The basic concept is analytic continuation.
https://en.wikipedia.org/wiki/Analytic_continuation
http://math.columbia.edu/~nsnyder/tutorial/lecture4.pdf

The second is specific for analytic continuation of zeta function.
 

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