MHB Understanding the Linear Independence of Columns in a 3x5 Matrix

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In a 3x5 matrix A, the columns cannot be linearly independent due to the rank constraint. The maximum rank of A is 3, meaning it can have at most 3 linearly independent columns. Since A has 5 columns, this guarantees that at least some columns must be linearly dependent. Additionally, the rank also reflects the number of linearly independent rows, reinforcing the limitation. Therefore, the columns of a 3x5 matrix must be linearly dependent.
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If A is a 3x5 matrix, explain why the columns of A must
be linearly independent.

i thought if A is 3x5, the columns of A must be linearly dependent, since
the rank is at most 3, and the rank is the number of linearly independent columns in A.
but there are 5 columns in A, so the columns of A must be linearly dependent :/
 
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Yuuki said:
i thought if A is 3x5, the columns of A must be linearly dependent, since
the rank is at most 3, and the rank is the number of linearly independent columns in A.
but there are 5 columns in A, so the columns of A must be linearly dependent :/
Correct! (Yes) (You might perhaps have added that the rank is also the number of linearly independent rows in A, which is why the rank is at most 3.)
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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