"Understanding the Period of a Function f{ax + b}

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Homework Help Overview

The discussion revolves around understanding the period of a function expressed in the form f(ax + b). The original poster seeks clarification on the relationship between the parameters a, b, and the period of the function.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of the period of a function and its implications when transformed by linear functions. There is a focus on the correct interpretation of the parameters a and b in relation to the period.

Discussion Status

Participants are actively engaging with the definitions and relationships involved, with some suggesting alternative interpretations of the period based on the transformations applied to the function. A productive direction has emerged regarding the correct expression for the period.

Contextual Notes

There is some confusion regarding the parameters and definitions, particularly whether the period should be expressed as p/a or b/a. The discussion reflects an ongoing examination of these assumptions.

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Homework Statement



If f{x + p } = f{x} for all x..then p is called the period of the function.

This part is clear to me.Now the book says...

The period of the function f{ax + b} is b/a.Can someone lead me through.

Homework Equations



N/A
 
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Hi physixguru! :smile:

hmm :confused: … I think they must mean:
The period of a function f for which f{ax + b} = f{x} for all x is b/a. :smile:

EDIT: ooh … that's not right … thinks … I think they mean the same f, and it's p not b:

The period of f{ax + b} is p/a. :smile:

Hint: put g(x) = f(ax + b). Then … ? :smile:
 
Last edited:
I need the xplanation.
 
Hi! see edit of previous post.

 
If f is a function with period p, that is, if f(x+ p)= f(x) for all x, then f completes one period as x goes from 0 to p. g(x)= f(ax+ b) will complete a period as ax+ b goes from 0 to p. That is, from ax+ b= 0 so x= -b/a, to ax+ b= p so x= (p- b)/a that is a "distance" of (p- b)/a- (-b/a)= p/a- b/a+ b/a. If f has period p, then f(ax+ b) has period p/a, not b/a.
 
Thats right...i was cured when you told me that it was p/a.
thnx all.
 

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