Mar 30, 2015 #31 Raghav Gupta Messages 1,010 Reaction score 76 That explains it all. Thank you everybody.
Apr 4, 2015 #32 K V N Murty Messages 1 Reaction score 0 period of tan pi x = 1 as the graph for x = -1/2 to 1/2 repeats. period of x - [ x ] = 1 as the graph repeats for [n , n-1). Hence, the period of the given function is 1. AGain for Sin (2 pi x ) + x - [x] also the period is 1, for a similar reason.
period of tan pi x = 1 as the graph for x = -1/2 to 1/2 repeats. period of x - [ x ] = 1 as the graph repeats for [n , n-1). Hence, the period of the given function is 1. AGain for Sin (2 pi x ) + x - [x] also the period is 1, for a similar reason.