Understanding the Physics Behind Bicycle Helmet Design and Use

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The discussion focuses on the physics principles relevant to bicycle helmet design, particularly energy, momentum, and acceleration. It clarifies that during a crash, kinetic energy is not converted to potential energy but rather to mechanical energy that deforms the helmet. Helmets are designed to increase the time of deceleration, thereby reducing the force experienced by the head upon impact. Additionally, helmets help distribute the impact force over a larger area, further enhancing safety. Understanding these concepts is crucial for effectively demonstrating the physics behind helmet usage.
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I am doing a lesson on Energy and Momentum and I am asked to write a report that includes sample calculations and examples, a thorough discussion of the principles of physics pertaining to energy and momentum, and apropriate diagrams and notations to demonstrate my understanding between the design and use of the helmet.

I am looking up google for information, and having some difficult time finding the right information, I appreciate if I could get some recommended links. I think they are asking me to demonstrate how kinetic energy is converted to potential energy during a crash but not quite sure how momentum is used (any help is appreciated) in the physics of helmets.
 
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In a crash kinetic energy isn't converted to potential energy.
It is converted into the energy needed to deform and break the helmet (mechanical energy)
A more useful approach is accelearation. You know about f = ma?
The point of the helmet is to slow down the rate at which your head stops, by increasing the 't' in a = v / t, by taking time to deform it slows your head down more gently and so reduces the force.
 
Last edited by a moderator:
mgb_phys said:
The point of the helmet is to slow down the rate at which your head stops, by reducing the 't' in a = v / t.
Make that increasing the time.

A helmet does two things: 1 - increases the distance of decleration, which increases the time of deceleration, which decreases the rate of decleration, which decreases the force. 2 - spreads the point of impact over a larger area.
 
Argghh, typo and now I can't edit it.
 
mgb_phys said:
Argghh, typo and now I can't edit it.

I fixed it for you. :biggrin:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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