Understanding the Unusual Repulsion of Antiparallel Magnetic Fields

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SUMMARY

The discussion focuses on the repulsive force between two parallel wires carrying opposing currents, specifically addressing the mathematical explanation using Lorentz force and magnetic energy density. The repulsive force is calculated using the formula F = I x B and the stored magnetic energy density, as outlined in Smythe's "Static and Dynamic Electricity." The key finding is that the force is positive, indicating that the repulsive force acts to increase the stored magnetic energy, contrasting with mechanical systems where forces typically act to reduce energy. This phenomenon highlights the unique behavior of magnetic fields compared to electric fields.

PREREQUISITES
  • Understanding of Lorentz force and its application in electromagnetism
  • Familiarity with magnetic energy density calculations
  • Knowledge of inductance and its formulas, particularly in relation to wire pairs
  • Basic principles of electromagnetism as outlined in Smythe's "Static and Dynamic Electricity"
NEXT STEPS
  • Study the Lorentz force law in detail, focusing on its implications in electromagnetism
  • Explore the concept of magnetic energy density and its calculation methods
  • Investigate the relationship between inductance and magnetic energy in wire configurations
  • Review sections 7.18 and 8.02 of Smythe's "Static and Dynamic Electricity" for deeper insights into magnetic interactions
USEFUL FOR

Physicists, electrical engineers, and students studying electromagnetism who are interested in the behavior of magnetic fields and their interactions with current-carrying conductors.

superaznnerd
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If one wire has current running through it to the right, and another wire below it has current running it through the left...
Why would they repel each other??
Can someone explain mathematically/ using right hand rule??

Thanks
 
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There are two ways to calculate the repulsive force between two wires with opposing currents I in the z direction and separation a (The first way doesn't count)

1) Use Lorentz force, F = I x B = μ0 I2/2πa

2) Calculate the total stored magnetic energy density over volume and take the partial derivative with respect to the wire separation.

The transverse magnetic field components for the two wires separated by distance a are given in Smythe, Static and Dynamic Electricity, third edition, Section 7.09 (3) (4). The stored magnetic energy per unit length is given by (See Smythe 8.02 (3))

W = 1/(2μ0)∫v B2 dV where B2= Bx2 + By2

and the force per unit length by (See Smythe 8.01 (4))

Fa = +∂W/∂a

It is obvious that that W is minimum when the two wires are close together, because the magnetic fields cancel, so the stored magnetic energy increases with increasing a, and Fa is therefore positive.

3) The inductance of the wire pair per unit length is (Smythe 8.12 (11)

L = (μ0/4π)[1+ 4 Ln(a/c)]

where a is wire separation and c is wire radius.

The stored magnetic energy can then be written as (see Smythe 8.08 (1))

W = ½LI2

Then the force is

Fa = +∂W/∂a as before.

Bob S
 
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In post #2, the calculated force between the two conductors is

Fa = +∂/∂a [1/(2μ0)∫v B2 dV] (with a plus sign)

This is very unusual, and unexpected, because the repulsive force is in the direction of increasing the stored magnetic energy.

In a mechanical system, like a compressed spring, W = ½ k x2, so the force is

Fx = −∂W/∂x = −kx (with a minus sign).

So the force is in a direction to reduce the stored mechanical energy.

Smythe, in Static and Dynamic Electricity, third edition, sections 7.18 and 8.02, discusses the sign difference at some length. In the magnetic case, the external circuit provides energy to maintain a constant current in the conductors as the conductor is moved. Smythe states "The [magnetic case] is exactly the opposite of the electric case, where the force on equal and opposite charges tends to bring them together and destroy the electric field."

Bob S
 
Last edited:

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