Understanding Trig Notation: What Does Sin(90°-θ) Mean?

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SUMMARY

The discussion centers on the trigonometric identity Sin(90° - θ), which is established as equal to Cos(θ). Participants clarify that Sin(90° - θ) can be derived from the properties of right-angled triangles, where the sine of an angle is the ratio of the opposite side to the hypotenuse. This relationship highlights the complementary nature of sine and cosine functions, confirming that Sin(90° - θ) = Cos(θ) for acute angles.

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  • Understanding of basic trigonometric functions, specifically sine and cosine.
  • Familiarity with right-angled triangle properties and angle relationships.
  • Knowledge of acute angles and their significance in trigonometry.
  • Basic algebra skills for manipulating trigonometric expressions.
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  • Study the derivation of trigonometric identities, focusing on complementary angles.
  • Explore the unit circle and its application to trigonometric functions.
  • Learn about the Pythagorean theorem and its role in trigonometry.
  • Investigate advanced trigonometric identities, such as the co-function identities.
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Students of mathematics, educators teaching trigonometry, and anyone seeking to deepen their understanding of trigonometric identities and their applications in geometry.

Feodalherren
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I'm solving some trig functions and ran into a notation that says

Sin(90°-θ)

What does it mean?

I know what Sin θ is and I know that Sin 90° = 1.
 
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Just in case it's important, Sin θ=

(2x)(9+4x^2)^(1/2) / (9+4x^2)
 
Do you know how sin(90°-θ) is related to cos(θ)?

What is the full problem?

ehild
 
Feodalherren said:
I'm solving some trig functions and ran into a notation that says

Sin(90°-θ)

What does it mean?

I know what Sin θ is and I know that Sin 90° = 1.

θ is some angle (we'll only deal with acute angles here) and then sin θ is the ratio of the opposite side to the hypotenuse in a right-angled triangle with one of its angles as θ. But if you look at that same triangle, you can deduce that the last angle must be
180° - 90° - θ = 90° - θ
because a triangle's angles add up to 180o.
And now, what is the cosine of that angle? That is, what is cos (90° - θ)? Well, since cos of an angle is the ratio between the adjacent side and the hypotenuse, these are exactly the same sides in the ratio of sin θ, so that means that sin θ = cos (90° - θ)
Can you use a similar procedure to find out what Sin(90°-θ) is?
 

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