Understanding Wave Function and Schrodinger Wave Equation

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A wave function describes the probability amplitude of a quantum system, allowing for the calculation of the probability of finding a system in a specific state at a given time. It is a mathematical construct that represents potential outcomes rather than a physical entity, and it does not propagate through space-time like classical waves. The Schrödinger equation, a partial differential equation, can be applied to quantum systems, including a simple pendulum, to determine energy levels through its time-independent form. The wave function's square gives the probability distribution for measurement results, emphasizing its role in quantum mechanics. Understanding these concepts is crucial for grasping the duality of light and the nature of quantum phenomena.
wasi-uz-zaman
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hi ,
can anyone please explain to me what is wavefunction - and can we apply schordinger wsve equation to simple pendulum.
thanks
 
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From my limited knowledge as of this moment, the way I think of wavefunction is basically a varying wave of numerous possibilities, it's upon observation which's when we break /collapse the wavefunction and make it definite.This is what happens in nature and how duality phenomena of light was discovered.

Schrodinger equation is a partial differential equation I am not sure whether there's a possibility of conversion from PDE to ODE. I will let other users give you a detailed explanation who are much knowledgeable on this.
 
wasi-uz-zaman said:
hi ,
can anyone please explain to me what is wavefunction - and can we apply schordinger wsve equation to simple pendulum.
thanks

A wave function is a function that describes the probability amplitude of a system. In simple terms, it can be used to determine the probability of finding a system in a certain state at a certain time :

http://en.wikipedia.org/wiki/Wave_function

Yes, you can use it to describe a classic pendulum.
 
wasi-uz-zaman said:
hi ,
can anyone please explain to me what is wavefunction - and can we apply schordinger wsve equation to simple pendulum.
thanks


Quantum mechanics only predicts the possible results of a measurement and the probability distribution of those results. We use the wavefunction\psi (x)
to calculate the probability distribution\left| {\psi (x)} \right|^2of the measurement results.\left| {\psi (x)} \right|^2gives us the probability of finding the particle at positionxwhen we measure the position. It is a mathematical construct that is not an observable, i.e. we do not measure any of its attributes. Most believe that it is not a real physical entity; it does not propagate in space-time like real classical waves do. Mathematically it is defined as a vector in a Hilbert space, which is a complex linear vector space.

Schrodinger's time dependent equation i\hbar \partial \psi (x,t)/\partial t = \hat H\psi (x,t)can be applied to any quantum system, including the quantum simple pendulum. Usually, however, we only want to determine the energy levels and we solve instead the time independent Schrodinger equation\hat H\psi _k = E_k \psi _k, which is the energy eigenvalue equation.

Best wishes
 
thnaks a lot
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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