Understanding why cyclic rule works

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The cyclic rule in thermodynamics states that the product of partial derivatives, such as (del x/del y)_z * (del y/del z)_x * (del z/del x)_y, equals -1 due to the nature of holding variables constant during differentiation. The negative sign arises from the rearrangement of the equation, specifically when considering the condition where dZ equals zero. This leads to the relationship (del x/del y)_z = - (del z/del y)_x / (del z/del x)_y. Additionally, the relationship (del z/del y)_x * (del y/del z)_x = 1 demonstrates that the apparent cancellation is valid only when the same variables are held constant. Understanding these relationships is crucial for grasping the cyclic rule's application in physical chemistry.
gloryofgreece
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I don't quite understand why cyclic rule works (from Pchem)

(del x/ del y)_z = part of x with respect to y, hold z constant

I don't know why is it negative 1?

del x/ del y)_z * del y/ del z)_x * del z/ del x)_y = -1
 
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You could derive it. Not sure if there is any other way to imagine it
\mathrm{d}z=\left.\frac{\partial z}{\partial x}\right)_y\mathrm{d}x+\left.\frac{\partial z}{\partial y}\right)_x\mathrm{d}y
Now to get \left.\frac{\partial x}{\partial y}\right)_z from the above equation just find the fraction \frac{\mathrm{d}x}{\mathrm{d}y} under the condition that \mathrm{d}z=0, i.e.
\left.\frac{\partial x}{\partial y}\right)_z=\left.\frac{\mathrm{d} x}{\mathrm{d} y}\right)_{\mathrm{d}z=0}=-\frac{\left.\partial z/\partial y\right)_x}{\left.\partial z/\partial x\right)_y}
The minus sign comes from rearranging the first equation.

Also
\left.\frac{\partial z}{\partial y}\right)_x=\frac{1}{\left.\frac{\partial y}{\partial z}\right)_x}
or
\left.\frac{\partial z}{\partial y}\right)_x\left.\frac{\partial y}{\partial z}\right)_x=1
The apparent cancellation is only possible since both derivatives have the same variables kept constant!
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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