Understanding why we compute surface area as we do

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SUMMARY

This discussion focuses on the differentiation process used to compute the surface area of geometric figures, specifically cylinders and spheres. The participants clarify that differentiating with respect to the z-coordinate is not solely due to its change but rather depends on the implicit relationships between the variables defined by the geometric shape. The choice of which variable to differentiate is influenced by the problem's context and the shape's domain, such as using rectangular coordinates for a semicircular domain.

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  • Understanding of differential calculus and partial derivatives
  • Familiarity with geometric figures, specifically cylinders and spheres
  • Knowledge of implicit functions and their relationships
  • Basic proficiency in coordinate systems, particularly rectangular coordinates
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  • Learn about implicit differentiation and its use in geometric contexts
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Students and educators in mathematics, particularly those studying calculus and geometry, as well as professionals involved in mathematical modeling and geometric analysis.

JD_PM
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Homework Statement



Captura de pantalla (521).png


Homework Equations



Captura de pantalla (524).png


The Attempt at a Solution


[/B]
The solution to this problem is known. I want to use this exercise as a model to understand how to proceed when calculating the surface area of a geometric figure.

Captura de pantalla (526).png

Captura de pantalla (527).png

Question:


1) Why do we differentiate with respect to z to get dS?

I'd say because in the constraining figure (in this case a cylinder which lies on the xy plane), while we move through the figure, we're changing ##z## coordinate.
I guess that if the cylinder were to lie on the, say, yz axis we'd differentiate with respect to x.

Am I right?

 

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JD_PM said:

Homework Statement



View attachment 240507

Homework Equations



View attachment 240508

The Attempt at a Solution


[/B]
The solution to this problem is known. I want to use this exercise as a model to understand how to proceed when calculating the surface area of a geometric figure.

View attachment 240509
View attachment 240510
Question:


1) Why do we differentiate with respect to z to get dS?

I'd say because in the constraining figure (in this case a cylinder which lies on the xy plane), while we move through the figure, we're changing ##z## coordinate.
I guess that if the cylinder were to lie on the, say, yz axis we'd differentiate with respect to x.

Am I right?
I wouldn't put it that way. As you move along the surface you are changing x and y also, so just because z is changing is not the reason. The sphere ##x^2 + y^2 + z^2 = 4a^2## defines any of its variables implicitly as functions of the other two variables. So you could consider ##y## as a function of ##x## and ##z##, ##x## as a function of ##y## and ##z##, or ##z## as a function of ##x## and ##y##. The reason to choose which one is usually given by looking at the particular problem and the shape and ease of working with the domain of the independent variables. In this problem, the ##x,y## domain is a semicircle whose equation is basically given in the problem so that is a reasonable choice. Whether to use rectangular coordinates in the first place is preferable is another question. I might have more to say about that later today if I have time.
 
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