Surface area bounded by 2 different planes

[chetzread]

Homework Statement

Find the surface area of portion of plane x + y + z = 3 that lies above the disc (x^2) + (y^2) < 2 in the first octant ...

Homework Equations

The Attempt at a Solution

Here's the solution provided by the author ...
I think it's wrong ... I think it should be the green coloured area + the black area ...

If it's only the black area , then the problem is find the surface area of portion of plane x + y + z = 3 that lies above the cylinder (x^2) + (y^2) < 2 in the first octant..

 

[chetzread]

Image here

 

[Mark44]

Homework Statement

Find the surface area of portion of plane x + y + z = 3 that lies above the disc (x^2) + (y^2) < 2 in the first octant ...

Homework Equations

The Attempt at a Solution

Here's the solution provided by the author ...
I think it's wrong ... I think it should be the green coloured area + the black area ...

No, it's just the black area.

If it's only the black area , then the problem is find the surface area of portion of plane x + y + z = 3 that lies above the cylinder (x^2) + (y^2) < 2 in the first octant..

That's not what they wrote. The disc they described consists of all the points in the x-y plane that lie inside the circle $x^2 + y^2 = 2$.

 

[chetzread]

No, it's just the black area.
That's not what they wrote. The disc they described consists of all the points in the x-y plane that lie inside the circle $x^2 + y^2 = 2$.

The disc here refers to the circle with radius 2 lie on the xy plane where z = 0?

 

[Mark44]

The disc here refers to the circle with radius 2 lie on the xy plane where z = 0?

Almost -- the radius is $\sqrt{2}$. And yes, the disc is in the x-y plane.