Undetermined system with no solutions?

[Questions999]

So I have the system { 2x+3y+z-3v=2 ;x-y+2z+v=0 ;3x+2y+3z-2v=-2} . I have to show that the system has no solutions.. I notice that it has more unknowns than equations so it is an undetermined system.If I form the matrix ? |(2 1 3 ) (3 -1 2) (1 2 3)| I notice that the determinant is diff from zero so this three vectors are linearly indipendent. Now how do I form a matrix using ( 2 0 -2) and these three vectors with the condition that they have a determinant diff from zero? Because if they have a determinant diff from zero,the system has no solutions.

 

[haruspex]

So I have the system { 2x+3y+z-3v=2 ;x-y+2z+v=0 ;3x+2y+3z-2v=-2} . I have to show that the system has no solutions.. I notice that it has more unknowns than equations so it is an undetermined system.If I form the matrix ? |(2 1 3 ) (3 -1 2) (1 2 3)|
I notice that the determinant is diff from zero so this three vectors are linearly independent.

Right, but what are you deducing from that?
If there are no solutions there must be a linear combination of the equations which eliminates all variables but not all constants. It's fairly easy to spot.

 

[Questions999]

I wrote the question in the wrong way..the answer on my textbook is " The system has no solutions"..I just have to show if the system has or not solutions...

 

[Questions999]

But if the system has no solutions the vectors forming the matrix including 2 0 -2 should be linearly indipendent /...

 

[haruspex]

But if the system has no solutions the vectors forming the matrix including 2 0 -2 should be linearly indipendent /...

Not sure what you mean by 'including 2 0 -2'. Do you mean the 5x3 matrix formed by moving the constants across to the left? The non-existence of solutions does not require all the equations to be linearly independent. Trivial example:
x - 1 = 0
x - 2 = 0
x - 2 = 0
In the OP, I can see a linear combination of the equations which eliminates all the variables but leaves a contradictory statement regarding the constants. That implies there are no solutions.
The det of |(2 1 3 ) (3 -1 2) (1 2 3)| is 0.