Unified gravity with electroweak through SU(2)xSU(2)xU(1)

[fxdung]

Consider symmetry SO(1,3)xU(1)=SU(2)xSU(2)xU(1) and puting a local spontaneous broken symmetry:
Φ→exp(iα^aτ^a)exp(iα^aτ^a)exp(i(β/2))Φ
The field Φ acquires vacuum expectation value: <Φ>=(0,v).
Then ΔL=½(0 v)(gC_μ^aτ^a+gA_μ^aτ^a+
½g'B_μ)²(0 v)^T.Then we find out three massive boson,one massless photon and two massless vector boson corresponding with 8 components of gravitation field h_μν
Is that correct?

 

[PeterDonis]

Is that correct?

Do you have a reference for this? PF does not allow discussion of personal theories.

 

[fxdung]

This is my theory.

 

[PeterDonis]

This is my theory.

Then it's off topic here. Thread closed.