Uniform angular acceleration - degrees per second?

[BlueSkyy]

Homework Statement

A wheel is subjected to uniform angular acceleration. Initially its angular velocity is zero. During the first 1-s time interval, it rotates through an angle of 88.6degrees.

(a) Through what angle does it rotate during the next 1-s time interval?
(b) Through what angle during the third 1-s time interval?

Homework Equations

a = (wf - wi)/(tf-ti)
360 degrees = 2*pi*radians

The Attempt at a Solution

i found a = 1.546, where do i go from here?

 

[Mentz114]

Have a look here
http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html

You need the rotational equivalent of s = 1/2 at^2

The usual units of angular acceleration are radians/sec^2, 'Radians per second per second'.

 

[BlueSkyy]

okay, i came up with 132.87 degrees using one of the equations, do i subtract 88.6 degrees (the original rotation?)

 

[BlueSkyy]

i am so confused, and everything i try is wrong

 

[Mentz114]

Yes, assuming you have calculated the angle turned in 2 secs. It's not very helpful to say "using one of the equations". But I think you are wrong because I'd expect more turn in the second period than the first ( because the speed is increasing linearly).