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hdp12
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Homework Statement
/* Intro, personal: I am taking Studio Physics 1 at FSU this summer semester. We have an online homework assigned weekly via a program called ExpertTA. This question has been giving me the HARDEST time and I seriously just need some help on it. I have completed and submitted sections a-g and all were correct. Part h), however, I must be doing wrong or something because I believe that I have tried every possibility that I can come up with. Whoever attempts to give this a shot, I genuinely appreciate it. I'm not one to usually ask for help, but like I said... I am stumped. */
PROBLEM:
A uniform disk of mass m and radius R can rotate about an axle through its center. Four forces are acting on it as shown in the figure. These forces are labeled F1, F2, F3, and F4. F2 and F4 act a distance d from the center of mass while the other two act on the outer edge of the disk. These forces are all in the plane of the disk.
RANDOMIZED VARIABLES:
m= 3.6 kg
R= 24 cm = 0.24 m
F1= 2.5 N
F2= 2.5 N
F3= 6.5 N
F4= 4.5 N
d= 3.5 cm = 0.035 m
a) Write an expression for the magnitude τ1 of the torque due to force F1
√ANSWER: τ1 = F1R
b) Calculate the magnitude τ1 of the torque due to force F1, in N·m
√ANSWER: τ1 = 0.6
[c) Write an expression for the magnitude τ2 of the torque due to force F2
√ANSWER: τ2 = F2d
d) Calculate the magnitude τ2 of the torque due to force F2, in N·m
√ANSWER: τ2 = 0.0875
[e) Write an expression for the magnitude τ3 of the torque due to force F3
√ANSWER: τ3 = 0
[f) Write an expression for the magnitude τ4 of the torque due to force F4
√ANSWER: τ4 = dF4sin(53)
g) Calculate the magnitude τ4 of the torque due to force F4, in N·m
√ANSWER: τ4 = 0.1258
h) Calculate the angular acceleration α of the disk about its center of mass in rad/s2. Let the counter-clockwise direction be positive.
PREVIOUS ANSWERS:
Xα=3.95
Xα=25.65
Xα=25.6519
Xα=25.66
Homework Equations
τ=rFsin(θ)
τ=Iα
α=τNET/I
[itex]\downarrow[/itex] Moment of Inertia of a uniform disk about its center of mass
I=[itex]\frac{1}{2}[/itex]mR2
The Attempt at a Solution
I don't recall how I got the first answer that I submitted, but I do for the last three.
Since the directions of the torques varies, the net torque will be calculated by adding the two ccw torques and subtracting the cw torque
τNET=τ1-τ2+τ4
Next I set up the angular acceleration equation using the net torque just written and the moment of inertia formula
α=τNET/I = (τ1-τ2+τ4 )/ ([itex]\frac{1}{2}[/itex]mR2)
This equation produces the answer in terms of m/s2, but the question clearly asks for radians so, using the equation where 1 rad = 0.24 m = R
α=(τ1-τ2+τ4 )/ ([itex]\frac{1}{2}[/itex]mR2)·[itex]\frac{1 rad}{R}[/itex]
This SHOULD give me the correct answer. And, plugging all of the numbers in, I get 25.6519 but that is allegedly incorrect.
Please help me.
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