Uniform circular motion car problem

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Homework Help Overview

The problem involves a cart with a person passing over a circular arch at a constant speed, questioning the dependency of the maximum speed on the mass of the cart and the person, or if it is independent of both. The context is uniform circular motion and centripetal force.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between gravitational force and centripetal force, questioning how these forces interact at the point of losing contact with the track. There is uncertainty about the role of mass in determining maximum speed.

Discussion Status

Some participants have provided hints regarding the equations involved and the conditions under which the cart would leave the track. There is ongoing exploration of the implications of mass and radius on the speed, with no explicit consensus reached.

Contextual Notes

Participants note potential errors in the equations presented and discuss the significance of the normal force being zero at the point of losing contact. The discussion is constrained by the need for clarity on the relationship between mass, radius, and speed.

S[e^x]=f(u)^n
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Homework Statement


a cart with a person in passes over a circular arch at a constant speed v who's radius is r. Does the maximum speed the cart can go without leaving the tracks depend on the mass of the person, the mass of the cart, both, or neither?


Homework Equations


Fg=mg -Gravitational Force
Fc=(mv^2)/2r? -Centripetal force
Fn=? -Normal force


The Attempt at a Solution


Fc=Fg-Fn
i honestly don't know where to go from here? can anyone offer any hints... i need to figure it out by tomorrow afternoon. my gut says it depends on neither, but from math I've fiddled around with it seems to indicate it depends on both
 
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S[e^x]=f(u)^n;1463608 said:

Homework Statement


a cart with a person in passes over a circular arch at a constant speed v who's radius is r. Does the maximum speed the cart can go without leaving the tracks depend on the mass of the person, the mass of the cart, both, or neither?


Homework Equations


Fg=mg -Gravitational Force
Fc=(mv^2)/2r? -Centripetal force
Fn=? -Normal force


The Attempt at a Solution


Fc=Fg-Fn
i honestly don't know where to go from here? can anyone offer any hints... i need to figure it out by tomorrow afternoon. my gut says it depends on neither, but from math I've fiddled around with it seems to indicate it depends on both
that "2" in the denominator of your Fc equation doesn't belong there. Your equation Fc = Fg -Fn is good.
What is the value of Fn just as the cart would leave the tracks?
 
sorry about the 2, i don't know why i put it there. anyway Fn would be 0 on the cart, but so would the Fn for the person inside... wouldn't it? in which case the cart would leave the tracks at the same speed regardless of whether there was a person in there?... but is it still dependent on the weight of the car?
 
Well, weight (mg) is pulling down while the centrifugal force (mv2/r) would cause the cart to go tangent to the track. For the cart to stay on the track those two forces must be equal.

Set the forces equal and see what happens with respect to mass.
 
S[e^x]=f(u)^n;1463608 said:

Homework Statement


a cart with a person in passes over a circular arch at a constant speed v who's radius is r. Does the maximum speed the cart can go without leaving the tracks depend on the mass of the person, the mass of the cart, both, or neither?


Homework Equations


Fg=mg -Gravitational Force
Fc=(mv^2)/2r? -Centripetal force
Fn=? -Normal force


The Attempt at a Solution


Fc=Fg-Fn
i honestly don't know where to go from here? can anyone offer any hints... i need to figure it out by tomorrow afternoon. my gut says it depends on neither, but from math I've fiddled around with it seems to indicate it depends on both

what is special when the car is driven at the maximum speed so that it is just about to lose contact with the ground is that the normal force is zero. Isolate for the speed and you will have your answer. (btw, you should have mv^2/r, not mv^2/2r)
 
nrqed said:
what is special when the car is driven at the maximum speed so that it is just about to lose contact with the ground is that the normal force is zero. Isolate for the speed and you will have your answer. (btw, you should have mv^2/r, not mv^2/2r)

thanks, from what i can figure out the velocity at which the cart(regardless of mass) leaves the tracks is dependent solely on the square root of the radius. which sounds about right to me
 
S[e^x]=f(u)^n;1463947 said:
thanks, from what i can figure out the velocity at which the cart(regardless of mass) leaves the tracks is dependent solely on the square root of the radius. which sounds about right to me

correct. (and it depends on the acceleration due to gravity...the max speed on th emoon would be different ;-) )
 
thanks!
 

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