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## Homework Statement

A purse at radius 1.90 m and a wallet at radius 2.60 m travel in uniform circular motion on the floor of a merry-go-round as the ride turns. They are on the same radial line. At one instant, the acceleration of the purse is (1.70 m/s2) + (4.60 m/s2). At that instant and in unit-vector notation, what is the acceleration of the wallet?

## Homework Equations

Tan(theta)= -(V^2/r)sin(theta)/-(V^2/r)Cos(theta)

A=V^2/r

T(period)=2pir/v

## The Attempt at a Solution

I used the original components of the purse to determine the angle created from the acceleration components

1) Tan(theta)= (4.6m/s^2)/(1.70m/s^2)

Arc Tangent (4.6/1.7)=theta and I found theta=69.72 degrees

next, I used the angle to determine the new components of the wallet using the same velocity but at a different radius (2.6m)

2) 2.6 Cos69.72= acceleration of wallet about x = .901m/s^2

2.6 sin69.72 = acceleration of wallet about y = 2.44m/s^2

-I put those components into the unite vector notation and got the problem wrong... I'm wondering why, if anyone could please help. thanks