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Uniform circular motion of satellite

  1. Feb 11, 2008 #1
    1. An Earth satellite moves in a circular orbit 735 km above the Earth's surface. The period of the motion is 99.3 min. (a) What is the speed of the satellite?(b) What is the magnitude of the centripetal acceleration of the satellite?



    2. a = v^2/r

    T=2(pi)r/v


    3. i needed the solution in meters per second and found r = 735000 and T =5958. I plugged into the equations and solved and get 775 m for the speed and .818 for the magnitude. Both answers are incorrect but I'm unable to come up with the correct ones.
     
  2. jcsd
  3. Feb 11, 2008 #2
    735km is the distance above the surface, r should be the distance from the point it is rotating around
     
  4. Feb 11, 2008 #3
    right so would you add the radius of the earth to 735 as well?
     
  5. Feb 11, 2008 #4
    nevermind i got it. thanks!
     
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