Uniform Circular motion problem,

Click For Summary

Homework Help Overview

The discussion revolves around a problem related to uniform circular motion, specifically calculating the centripetal acceleration of wind particles at a certain distance from a hurricane's eye. The scenario involves converting units and applying the centripetal acceleration formula.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the centripetal acceleration formula, Ac=V^2/r, and the importance of unit consistency in calculations. There are attempts to substitute values into the equation, with some participants questioning their unit conversions.

Discussion Status

The conversation has progressed with participants sharing their attempts and corrections regarding unit conversions. Some guidance has been provided on ensuring that all measurements are in the correct SI units, and there is acknowledgment of successful calculations by one participant.

Contextual Notes

Participants are working under the constraints of homework rules, focusing on understanding the process rather than arriving at a final answer immediately. There is an emphasis on the importance of unit conversion in physics problems.

naham1866
Messages
4
Reaction score
0
1. At a distance of 25km from the eye of a hurricane, the wind is moving at 180km/h in a circle. What is the magnitude of the centripetal acceleration, in meters per second squared, of the particles that make up the wind?


Homework Equations


Ac=V^2/r = 4∏^2r/T^2 = 4∏^2rf^2


The Attempt at a Solution


Ac=V^2/r

The answer is 0.10m/s but I just can't seem to get it right.
 
Physics news on Phys.org
naham1866 said:
1. At a distance of 25km from the eye of a hurricane, the wind is moving at 180km/h in a circle. What is the magnitude of the centripetal acceleration, in meters per second squared, of the particles that make up the wind?


Homework Equations


Ac=V^2/r = 4∏^2r/T^2 = 4∏^2rf^2


The Attempt at a Solution


Ac=V^2/r

The answer is 0.10m/s but I just can't seem to get it right.

You have the right equation in your attempt. Fill in the numbers for velocity V and radius r, and be sure to stay consistent in your units. Show us that work...
 
Okay so I got Ac=180km/h^2/25km

Problem is that it doesn't give me 0.10m/s
 
naham1866 said:
Okay so I got Ac=180km/h^2/25km

Problem is that it doesn't give me 0.10m/s

You need to fix the units. You need to convert everything into meters, kilograms and seconds (the mks standard SI system of units). If you mix units like seconds and hours up, you won't get the right answers.

So convert everything you are given into mks units, and plug those quantities into the equation. Carry units along in the equation, and if you have the same units in numerator and denominator, you can cancle them out. Like m/m = 1, and s^2/s = s, and so on.

Now show us what you get...
 
Haha YES! I Did it! I went out and on my way back home I remembered that I had to change from kilometers to meters, so here's what I did.

180km/h / 60 = 3m/min /60 = 0.05m/s
25km / 1000 = 0.025m
Ac = V^2/r
Ac = 0.05m/s^2/0.025m
Ac= .10m/s
YES! :D
 
Thank you vey much for the help
 
naham1866 said:
Thank you vey much for the help

You are welcome. Learning to carry units along in your calculations is a huge trick, IMO. I still remember the first time I learned that wey back in undergrad many years ago.
 

Similar threads

Replies
55
Views
3K
Replies
1
Views
916
  • · Replies 7 ·
Replies
7
Views
3K
Replies
11
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K