Uniform circular motion problems

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Homework Help Overview

The discussion revolves around uniform circular motion, specifically analyzing the forces acting on a pilot during a vertical dive in a circular arc. The problem involves calculating the force exerted by the airplane seat on the pilot and determining the radius of the circular arc based on given parameters.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between centripetal force and gravitational force acting on the pilot. Questions arise regarding the calculations of forces and the interpretation of acceleration in terms of g.

Discussion Status

Some participants have provided guidance on understanding the forces involved, particularly how centripetal force relates to the normal force exerted by the seat. There is an acknowledgment of confusion regarding the calculations, but progress is being made as participants clarify their reasoning.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available and the methods they can use to arrive at their answers. The discussion reflects an exploration of assumptions related to forces and accelerations in the context of circular motion.

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[SOLVED] Uniform circular motion problems

Homework Statement


A pilot of mass 50kg comes out of a vertical dive in a circular arc such that his upward acceleration is 8.5g

Homework Equations


a) What is the magnitude of the force exerted by the airplane seat on the pilot at the bottom of the arc?
b) If the speed of the plane is 345 km/h, what is the radius of the circular arc?

The Attempt at a Solution


I've done F = ma, so 50 x 8.5 = 425, which is massively as the answer is 4659.75N

At the bottom of the ark the upward acceleration is the same as the magnitude of its centripetal acceleration (I think) therefore r = v^{2} / a, which comes to 14002.94, which is also massively wrong as the answer provided is 110m

I tried alsorts of other ways too but they never match the answers provided, what am I missing.
 
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You're not too far off

So draw the plane and all the forces acting on the poor pilot(who is pulling nearly 9 Gs and probably about to black out or rip his plane apart)

The centripetal FORCE acting on him is his mass times the centripetal acceleration(which is given in the problem as you correctly saw). What is the CAUSE of the centripetal force? ie what is pushing on him that hard? The seat. So the centripetal force is part of the answer. Is that all?

Also just good 'ol gravity is acting on him, pushing him straight down. That means the seat is exerting an equal normal force

The answer will be Fcent+Fnormal=Fouch
 
Ok so I've now done:
50 x 9.81 x 8.5 = 4169.25
50 x 9.81 = 490.5
4169.25 + 490.5 = 4659.75

but I'm a bit confused as to why I times gravity for when working out Fcent.

I also assumed that the answer to a, would help me with b; but I'm still getting the answer wrong
 
g represents an acceleration, it's in units of acceleration. A plain old unitless number(8.5) times g is also going to be an acceleration

It is customary to say the acceleration in terms of g, they could say "oh it's 83.3 m/s^2" or they could say "oh it's 8.5 times the acceleration caused by gravity" which immediately tells you he's being pushed into his seat with 8.5 times more force than normal, and pilots normally have a good sense of what the human body can stand(even trained fighter pilots don't pull more than 7 or 8 gs for just seconds)and their plane can stand

For b)You found the centripetal acceleration as PART of a(it wasn't the final answer!), and you're given v, and you know r=v^2/a
 
Oh right, the "he's being pushed into his seat 8.5 times more force than normal" got lightbulb above my head appear then thanks.

and for b)
r = 95.83^2 / (9.81 x 8.5)
r = 110.13

correct, thank you
 

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