Uniform circular motion proportionality question

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SUMMARY

In the discussion, David analyzes the effects of changing the radius of rotation on the period of a sling's motion. When the radius is doubled, the new period T2 is calculated as T2 = sqrt(2) * T1, indicating that T2 is approximately 1.414 times larger than the original period T1. Conversely, when the radius is halved, the period T is reduced to T/sqrt(2), resulting in a period that is approximately 0.707 times the original. This analysis utilizes the equation for centripetal acceleration, ac = (4π²r) / T², to derive the relationships between the periods and radii.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula.
  • Familiarity with the concepts of period and frequency in circular motion.
  • Basic algebra skills for manipulating equations.
  • Knowledge of square roots and their properties in mathematical expressions.
NEXT STEPS
  • Study the derivation of the centripetal acceleration formula ac = (4π²r) / T².
  • Learn how to apply the principles of circular motion to different physical scenarios.
  • Explore the relationship between radius, mass, and force in rotational dynamics.
  • Investigate the effects of varying forces on the period of rotation in uniform circular motion.
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Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators looking for clear examples of period and radius relationships in rotational dynamics.

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Homework Statement



David spins a sling in a horizontal circle above his head. What would happen to the period of rotation if he applied the same force and the length was a) doubled, b) halved

Homework Equations



ac = (4π2r) / T2

The Attempt at a Solution



Just not sure what to do in general, I tried a few different things like this:

r \alpha T2

2r \alpha T2
r \alpha T2/2

Then compared T2 and T2/2
square rooted both of them

T and T/sqrt(2)

1/sqrt(2) is 0.7, which is the answer to b), even though I was trying to do a).

edit: think I figured it out

I can just equate T and T/sqrt(2) can't I? The first T is Ta, the second is Tb, and that equation is saying that Ta is .7x smaller than Tb, in other words, Tb is 1.4x larger, right?
 
Last edited:
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My approach would be to solve the formula for T:
T1 = 2π*sqrt(mR/F)
I wrote that T1 to indicate it is the original period.
When R is doubled, you get
T2 = 2π*sqrt(m2R/F) and I wish I could make that 2R a red 2 to make it easier to follow. That 2 needs to go out of the sqrt where it becomes a root 2 and move to the front so you can see
T2 = sqrt(2)*2π*sqrt(mR/F) = sqrt(2)*T1
It is an excellent technique; works every time!
 

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