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A body of mass 81.7g is moving in a circular path of radius 0.65m. If we calculate the centrifugal force on it to have a magnitude of 0.35N, what is the period of revolution? (2 decimals, UNITS!)(p = 3.14)

2. Homework Equations :

I'm given the following equations:

a = v^2/r

v = Circumference/Period = 2pi/T

a = 4pi^2r/T^2

F = Mg

F = ma

3. The Attempt at a Solution :

I took .35 = mv^2/r so .35 = 81.7v^2/.65 so v = .5276

then I took T = 2pir/v so T = 2pi(.65)/.5276 so T =7.736

I got this wrong when I entered it. I may have rounded wrong at the end or didn't do it right in the first place Any help would be appreciated.