Unit analysis - using measurements as variables - correct (?)

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Homework Help Overview

The original poster attempts to determine the side length of a square garden with an area of 25 cm², while questioning the treatment of the unit "cm" as a variable in mathematical expressions. The discussion revolves around unit analysis and the algebraic manipulation of measurements.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between numerical values and their corresponding units, questioning whether units can be treated as variables in calculations. Some participants discuss the implications of squaring both numbers and units in the context of area.

Discussion Status

Some participants provide insights into the nature of physical quantities, affirming that units are integral to measurements and can be manipulated algebraically. However, the original poster's specific question about treating "cm" as a variable remains open for further exploration.

Contextual Notes

The original poster seeks clarification on the mathematical correctness of their approach to unit analysis, indicating a potential misunderstanding of how units interact with numerical values in algebraic expressions.

Wolfowitz
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Homework Statement


Currently, I'm expected to find the side length of a square garden whose area is 25cm2. Of course, we're talking about a square here, and since the area of a rectangle is l * w, and, when talking about a square, l = w, the area of a square is S2. Of course, I know each side length is going to be 5cm - that's rather obvious. Instead, I'm asking as to whether I should treat the actual measurement, "cm", as a variable.

(e.g.

25cm^2 = squareroot[25cm^2] * squareroot[25cm^2]
25cm^2 = squareroot[25] * squareroot[25] * squareroot[cm^2] * squareroot[cm^2]
25cm^2 = 5 * 5 * cm * cm
25cm^2 = 25*cm^2
25cm^2 = 25cm^2.)

Please pay attention to how I'm treating cm as a variable - is it mathematically correct to do this? That's my question.

If not, my question would be this:

How do you algebraically find the final unit of measurement in which your final answer will be presented, in this question, of course.
 
Last edited:
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No. "cm" is a unit of measurement. Length, which you called, l, is a variable. Width, which you called, w, is a varaible. Both the numbers, l and w, count centimeters.
 
Yes, in essence, a physical quantity consists of a number and a unit. The unit can be treated as something that is multiplied by the number (since you have 5 units of 1 cm). As a result, when you square the quantity, you square both the number and the unit. (The square of a product of two numbers is equal to the product of the square of those two numbers).

(5 cm)2 = 52 cm2 = 25 cm2

In reverse, it is as follows:

(25 cm2)1/2 = (25)1/2 (cm2)1/2

= 5 cm

I guess that's basically what you wrote.
 
cepheid said:
Yes, in essence, a physical quantity consists of a number and a unit. The unit can be treated as something that is multiplied by the number (since you have 5 units of 1 cm). As a result, when you square the quantity, you square both the number and the unit. (The square of a product of two numbers is equal to the product of the square of those two numbers).

(5 cm)2 = 52 cm2 = 25 cm2

In reverse, it is as follows:

(25 cm2)1/2 = (25)1/2 (cm2)1/2

= 5 cm

I guess that's basically what you wrote.

Thanks a bunch!
 

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